Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
Does GMAT RC seem like an uphill battle? e-GMAT is conducting a free webinar to help you learn reading strategies that can enable you to solve 700+ level RC questions with at least 90% accuracy in less than 10 days. Sat., Oct 19th at 7 am PDT
Re: In Set T, the average (arithmetic mean) equals the median. Which of th
[#permalink]
Show Tags
10 Feb 2015, 09:06
2
4
Bunuel wrote:
In Set T, the average (arithmetic mean) equals the median. Which of the following must be true?
I. Set T consists of evenly spaced numbers. II. Set T consists of an odd number of terms. III. Set T has no mode. IV. None of the above.
A. I only B. I and II C. II and III D. I, II, and III E. IV only
Kudos for a correct solution.
I. consider T (1, 2, 3) median=mean=2. Consider T (5, 9, 2, 19, 10) median=mean=9 II. Consider T (1, 2, 3) median=mean=2. Consider T (1, 1, 1, 1) median=mean=1 III. Consider T (1, 2, 3) mean=median=2 and there is no mode. Consider T (1, 1, 1) median=mean=1 and mode is 1.
Answer E.
_________________
learn the rules of the game, then play better than anyone else.
None of the proposed statements must be true; to prove this, you might consider a hypothetical: Set T could be [1,1, 3, 3], in which the average and median are both 2. This set proves I, II, and III wrong. (Note: This set has two modes, 1 and 3)
_________________
In Set T, the average (arithmetic mean) equals the median. Which of th
[#permalink]
Show Tags
18 Dec 2016, 13:45
This is an Excellent Question. Here is my take on this one =>
Firstly,
Quote:
For any evenly spaced set => Mean = Median = Average of the first and the last term.
Also =>
Quote:
Sum of deviations around the mean = Zero
Now We are told that a Set T is such that its mean = median We are asked which of the statements must be true.
Statement 1--> T is evenly Spaced
Consider two sets => 5,6,7,8,9,10,11 Mean = Median=8 Now Removing 7 and 9 wont affect the mean as 8-7 will be balanced by 8-9 and the sum of deviations around 8 will still be zero. Hence 5,6,8,10,11 => Mean = 8 and Median = 8 But the above set isn't every spaced.
Hence this statement is not always true. Statement 2=>
Consider a set => 7,7,7,7 Here => Mean=Median=7 And the number of terms is even. Hence this statement also isn't always true.
Statement 3--> Consider a set => 7,7,7,7 Here Mode = 7 Hence Set T will can have a mode=> The statement isn't always true. Statement 4--> None of the above => TRUE.
None of the proposed statements must be true; to prove this, you might consider a hypothetical: Set T could be [1,1, 3, 3], in which the average and median are both 2. This set proves I, II, and III wrong. (Note: This set has two modes, 1 and 3)
So, in conclusion we can takeway from this question that for an evenly spaced set mean=median does not necessarily mean that the vice versa is true. Just because for a set mean = median does not render the set as an evenly spaced one.
_________________
Consider giving me Kudos if you find my posts useful, challenging and helpful!
None of the proposed statements must be true; to prove this, you might consider a hypothetical: Set T could be [1,1, 3, 3], in which the average and median are both 2. This set proves I, II, and III wrong. (Note: This set has two modes, 1 and 3)
So, in conclusion we can takeway from this question that for an evenly spaced set mean=median does not necessarily mean that the vice versa is true. Just because for a set mean = median does not render the set as an evenly spaced one.
Re: In Set T, the average (arithmetic mean) equals the median. Which of th
[#permalink]
Show Tags
22 Sep 2019, 22:09
Hello from the GMAT Club BumpBot!
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
close
49% (01:19) correct 
