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Bunuel
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In the above correctly worked addition sum, A,B,C and D represent diff 19 May 2016, 03:03
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78% (02:11) correct 22% (02:13) wrong based on 233 sessions

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In the above correctly worked addition sum, A,B,C and D represent different digits, and all the digits in the sum are different. What is the sum of A,B,C and D?

A. 23
B. 22
C. 18
D. 16
E. 14

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B
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In the above correctly worked addition sum, A,B,C and D represent diff 19 May 2016, 07:36
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Bunuel

In the above correctly worked addition sum, A,B,C and D represent different digits, and all the digits in the sum are different. What is the sum of A,B,C and D?

A. 23
B. 22
C. 18
D. 16
E. 14

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p003-8.gif
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The first thing that we can say for sure is that D =1.. as B+5 or B+5+1 = 10*D + 4... and B is a digit....

Now A + C = 13, as None of A or C can be 1 as D =1.. so there are no combinations of A and C that can equal just 3..

Now from tens digit 5+B+1 = 14.... so B = 14-6=8....

so \(A+B+C+D= A+C+B+D = 13+8+1=22..\)
B
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In the above correctly worked addition sum, A,B,C and D represent diff 19 May 2016, 08:59
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'B' should be the answer.

Sum of two digits is giving three digits as the answer.

D must be 1

Now there could be two possibilities:-

Case 1:- A+C= 3

In this case 'B' would be 9. Hence sum off all digits will be 3+9+1= 13 (But this is not in the option)

Case 2:- A+C= 13

In this case 'B' would be 8. Hence sum of all digits would be 13+8+1= 22
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In the above correctly worked addition sum, A,B,C and D represent diff 19 May 2016, 09:30
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Divyadisha
'B' should be the answer.

Sum of two digits is giving three digits as the answer.

D must be 1

Now there could be two possibilities:-

Case 1:- A+C= 3

In this case 'B' would be 9. Hence sum off all digits will be 3+9+1= 13 (But this is not in the option)

Case 2:- A+C= 13

In this case 'B' would be 8. Hence sum of all digits would be 13+8+1= 22
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Hi,

the high lighted portion cannot be a possiblity.....
Quote:
and all the digits in the sum are different
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..
this means NOT ONLY A,B,C and D are different BUT ALSO they are different from existing digits 5,4 and 3
since you have correctly found D as 1, and A + C = 3, with both A and C as different digits..
so if A+C = 3..
two possiblities are
1) A and C are 0 and 3 but we already have 3 as one of the digits..
2) A and C are 1 and 2, but again D is already 1..
so NOT a possiblity..
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In the above correctly worked addition sum, A,B,C and D represent diff 19 May 2016, 10:03
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Bunuel

In the above correctly worked addition sum, A,B,C and D represent different digits, and all the digits in the sum are different. What is the sum of A,B,C and D?

A. 23
B. 22
C. 18
D. 16
E. 14

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Ans B
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In the above correctly worked addition sum, A,B,C and D represent diff 19 May 2016, 10:52
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chetan2u
Divyadisha
'B' should be the answer.

Sum of two digits is giving three digits as the answer.

D must be 1

Now there could be two possibilities:-

Case 1:- A+C= 3

In this case 'B' would be 9. Hence sum off all digits will be 3+9+1= 13 (But this is not in the option)

Case 2:- A+C= 13

In this case 'B' would be 8. Hence sum of all digits would be 13+8+1= 22

Hi,

the high lighted portion cannot be a possiblity.....
Quote:
and all the digits in the sum are different
..
this means NOT ONLY A,B,C and D are different BUT ALSO they are different from existing digits 5,4 and 3
since you have correctly found D as 1, and A + C = 3, with both A and C as different digits..
so if A+C = 3..
two possiblities are
1) A and C are 0 and 3 but we already have 3 as one of the digits..
2) A and C are 1 and 2, but again D is already 1..
so NOT a possiblity..
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Thanks for pointing out chetan2u. Overlooked the possibility that A,B,C and D are different from existing digits.
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In the above correctly worked addition sum, A,B,C and D represent diff 19 May 2016, 14:38
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D has to be 1 because we are adding two numbers that are lower than 100, so the total has to be lower than 200.

Because D = 1, we know that A + C can't be 3, because either A or C would also need to be 1 and that is not allowed, so the only other possibility is 13.

Now, (5+1) + B = 14, thus B = 8.

13 + 8 + 1 = 22.
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In the above correctly worked addition sum, A,B,C and D represent diff 08 Sep 2019, 01:56
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Bunuel

In the above correctly worked addition sum, A,B,C and D represent different digits, and all the digits in the sum are different. What is the sum of A,B,C and D?

A. 23
B. 22
C. 18
D. 16
E. 14

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p003-8.gif
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Bunuel and Other Experts, Please help with my query

Can we not have Zero has one of the value. It says different digits . So why not zero.

I mean can we take A =3 and C = 0 ,D=1, and B =9. Total comes to 13 ( I know its not in option) but I want to understand if ever we can consider Zero in such cases.

Thanks in advance for helping me understand.
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In the above correctly worked addition sum, A,B,C and D represent diff 23 Jun 2024, 12:20
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