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AD is parallel to CB, then ∠DAB = ∠ABC = b.
∠ABD = a, then ∠CAB = 2∠ABD = 2a.

Q. what is the measure of ∠ACB?

(1) ∠CAD = 90 = 2a + b
∠ACB = 180 - (2a+b)
= 180 - 90
= 90
SUFFICIENT

(2) ∠CBD = 60 = a + b
∠ACB = 180 - (2a+b)
= 180 - (a+b) - a
= 180 - 60 - a
= 120 - a
We need to know the value of ∠ABD or a.
NOT SUFFICIENT

FINAL ANSWER IS (A)

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AnthonyRitz

Statement 1)

Take triangle ACD.
Using angle sum property we get ACD +ADC = 90
ADC = DCB ( AD IS PARALLEL TO BC )
HENCE LACB = 90

Cant' we use the same approach for statement 2 ?
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kickmunch94
AnthonyRitz

Statement 1)

Take triangle ACD.
Using angle sum property we get ACD +ADC = 90
ADC = DCB ( AD IS PARALLEL TO BC )
HENCE LACB = 90

Cant' we use the same approach for statement 2 ?

No, you sadly cannot.

The problem is that you don't know whether angle ACD and angle BDC are equal; those are not opposite interior angles for the parallel lines AD and BC. Rather, you'd need AC and BD parallel, and we don't have that.
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