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In the correctlyworked addition operation above, A, B, C, and D each
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08 Jul 2017, 05:53
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77% (01:22) correct 23% (01:30) wrong based on 93 sessions
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Re: In the correctlyworked addition operation above, A, B, C, and D each
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08 Jul 2017, 06:14
A. D = 2B B. B > 5 C. C = 2A D. A < 5 E. D > B We know that D= 2B from the question itself so hold option A B) B can also be less than 5 (can take 0, 1, 2, 3, 4) rejected C) C=2A what if their is a carryover rejected D) A can take 1,2,3,4 but cannot take 0 rejected E) D can be equal to B when B=0 rejected Hence A
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Re: In the correctlyworked addition operation above, A, B, C, and D each
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08 Jul 2017, 06:21
mynamegoesonwhat if A = 3 and B = 9 C = 7 and D = 8 D = 8 is not equal to 2* B = 18
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Re: In the correctlyworked addition operation above, A, B, C, and D each
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08 Jul 2017, 06:28
Leo8 wrote: mynamegoesonwhat if A = 3 and B = 9 C = 7 and D = 8 D = 8 is not equal to 2* B = 18 Yes ohh i missed it the trick here was "A, B, C, and D each represent unique digits" so B=D=0 is not possible
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Re: In the correctlyworked addition operation above, A, B, C, and D each
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08 Jul 2017, 06:38
Leo8 wrote: mynamegoesonwhat if A = 3 and B = 9 C = 7 and D = 8 D = 8 is not equal to 2* B = 18 Wondering what would be the answer
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Re: In the correctlyworked addition operation above, A, B, C, and D each
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08 Jul 2017, 06:58
IMO ans must be D a< 5
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Re: In the correctlyworked addition operation above, A, B, C, and D each
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08 Jul 2017, 07:10
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Re: In the correctlyworked addition operation above, A, B, C, and D each
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08 Jul 2017, 12:09
Answer is D.
A. D = 2B => this cannot be true when value of B is equal to or greater than 5.
B. B > 5 => B can be less than 5 also, since unique digit can range from 0 to 9 without any conditions.
C. C = 2A => this cannot be true, when value of B is equal to or greater than 5. Let's say if B=5, A =4, then C=4+4+1=9, which conflicts the statement.
D. A < 5 => This condition must be true because if A is equal to or greater than 5, then it will have value equal to or above 10, but the given statement is > C is a unique digit, so value of C can be maximum 9.
E. D > B => This statement cannot be true when value of B is equal to or greater than 5. eg. If B=5, then D=0, which conflicts the given statement.



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Re: In the correctlyworked addition operation above, A, B, C, and D each
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08 Jul 2017, 12:17
Yes, you're doubling a twodigit number AB here (adding it to itself), and getting a twodigit number as a result. So AB has to be less than 50, or else you'd get a threedigit result. And if AB < 50, that means A < 5.
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Re: In the correctlyworked addition operation above, A, B, C, and D each
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08 Jul 2017, 19:07
If A>5, then the answer would be a three digit number, so A must be less than 5. Ans  D.
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Re: In the correctlyworked addition operation above, A, B, C, and D each
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08 Jul 2017, 22:30
It should be D as anything greater then 5 (for A position ) will give the end result in 3 digits
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Re: In the correctlyworked addition operation above, A, B, C, and D each
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14 Jul 2017, 22:33
IMO d



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Re: In the correctlyworked addition operation above, A, B, C, and D each
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03 Mar 2019, 06:25
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Re: In the correctlyworked addition operation above, A, B, C, and D each
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