GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 10 Dec 2018, 09:37

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

###### Events & Promotions in December
PrevNext
SuMoTuWeThFrSa
2526272829301
2345678
9101112131415
16171819202122
23242526272829
303112345
Open Detailed Calendar
• ### Free lesson on number properties

December 10, 2018

December 10, 2018

10:00 PM PST

11:00 PM PST

Practice the one most important Quant section - Integer properties, and rapidly improve your skills.
• ### Free GMAT Prep Hour

December 11, 2018

December 11, 2018

09:00 PM EST

10:00 PM EST

Strategies and techniques for approaching featured GMAT topics. December 11 at 9 PM EST.

# In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and li

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Current Student
Status: It always seems impossible until it's done!!
Joined: 29 Aug 2012
Posts: 1124
Location: India
WE: General Management (Aerospace and Defense)
In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and li  [#permalink]

### Show Tags

11 Nov 2017, 19:26
Top Contributor
00:00

Difficulty:

35% (medium)

Question Stats:

71% (01:53) correct 29% (01:47) wrong based on 61 sessions

### HideShow timer Statistics

Attachment:
File comment: Triangle

Capture.PNG [ 12.48 KiB | Viewed 1016 times ]

In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and line BG is parallel to line DF. What is the measure of angle A in degrees?

A. 25
B. 35
C. 45
D. 55
E. 65

_________________
PS Forum Moderator
Joined: 25 Feb 2013
Posts: 1217
Location: India
GPA: 3.82
In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and li  [#permalink]

### Show Tags

Updated on: 18 Nov 2017, 06:52
1
Gnpth wrote:
Attachment:
Capture.PNG

In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and line BG is parallel to line DF. What is the measure of angle A in degrees?

A. 25
B. 35
C. 45
D. 55
E. 65

Triangle BCD is an equilateral triangle, hence angle BCD=60°

In triangle DEF, angle DEF=180°-(40°+75°) = 65°

Hence angle A = 180°-(angle C + angle E)= 180°-(60°+65°) = 55°

Option D

Originally posted by niks18 on 11 Nov 2017, 19:57.
Last edited by niks18 on 18 Nov 2017, 06:52, edited 1 time in total.
Intern
Joined: 16 Feb 2017
Posts: 21
Re: In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and li  [#permalink]

### Show Tags

18 Nov 2017, 06:44
niks18 wrote:
Gnpth wrote:
Attachment:
Capture.PNG

In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and line BG is parallel to line DF. What is the measure of angle A in degrees?

A. 25
B. 35
C. 45
D. 55
E. 65

Triangle BCD is an equilateral triangle, hence angle BCD=60°

In triangle DEF, angle DEF=180°-(40°+75°) = 65°

Hence angle A = 180°-(angle B + angle E)= 180°-(60°+65°) = 55°

Option D

Hope you mean to say that in triangle ACE,
Angle C + Angle E + Angle A = 180
60 + 65 + A = 180
A = 180 - 125 = 55

It seems to be a typo to write angle B..
Thanks!
PS Forum Moderator
Joined: 25 Feb 2013
Posts: 1217
Location: India
GPA: 3.82
Re: In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and li  [#permalink]

### Show Tags

18 Nov 2017, 06:51
GMATAspirer09 wrote:
niks18 wrote:
Gnpth wrote:
Attachment:
Capture.PNG

In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and line BG is parallel to line DF. What is the measure of angle A in degrees?

A. 25
B. 35
C. 45
D. 55
E. 65

Triangle BCD is an equilateral triangle, hence angle BCD=60°

In triangle DEF, angle DEF=180°-(40°+75°) = 65°

Hence angle A = 180°-(angle B + angle E)= 180°-(60°+65°) = 55°

Option D

Hope you mean to say that in triangle ACE,
Angle C + Angle E + Angle A = 180
60 + 65 + A = 180
A = 180 - 125 = 55

It seems to be a typo to write angle B..
Thanks!

Hi GMATAspirer09

thank you for highlighting it. will correct it.
Re: In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and li &nbs [#permalink] 18 Nov 2017, 06:51
Display posts from previous: Sort by

# In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and li

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.