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In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and li

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In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and li  [#permalink]

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New post 11 Nov 2017, 19:26
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A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

71% (01:53) correct 29% (01:47) wrong based on 61 sessions

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In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and line BG is parallel to line DF. What is the measure of angle A in degrees?

A. 25
B. 35
C. 45
D. 55
E. 65

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In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and li  [#permalink]

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New post Updated on: 18 Nov 2017, 06:52
1
Gnpth wrote:
Attachment:
Capture.PNG

In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and line BG is parallel to line DF. What is the measure of angle A in degrees?

A. 25
B. 35
C. 45
D. 55
E. 65


Triangle BCD is an equilateral triangle, hence angle BCD=60°

In triangle DEF, angle DEF=180°-(40°+75°) = 65°

Hence angle A = 180°-(angle C + angle E)= 180°-(60°+65°) = 55°

Option D

Originally posted by niks18 on 11 Nov 2017, 19:57.
Last edited by niks18 on 18 Nov 2017, 06:52, edited 1 time in total.
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Re: In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and li  [#permalink]

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New post 18 Nov 2017, 06:44
niks18 wrote:
Gnpth wrote:
Attachment:
Capture.PNG

In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and line BG is parallel to line DF. What is the measure of angle A in degrees?

A. 25
B. 35
C. 45
D. 55
E. 65


Triangle BCD is an equilateral triangle, hence angle BCD=60°

In triangle DEF, angle DEF=180°-(40°+75°) = 65°

Hence angle A = 180°-(angle B + angle E)= 180°-(60°+65°) = 55°

Option D


Hope you mean to say that in triangle ACE,
Angle C + Angle E + Angle A = 180
60 + 65 + A = 180
A = 180 - 125 = 55

It seems to be a typo to write angle B..
Thanks!
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Re: In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and li  [#permalink]

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New post 18 Nov 2017, 06:51
GMATAspirer09 wrote:
niks18 wrote:
Gnpth wrote:
Attachment:
Capture.PNG

In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and line BG is parallel to line DF. What is the measure of angle A in degrees?

A. 25
B. 35
C. 45
D. 55
E. 65


Triangle BCD is an equilateral triangle, hence angle BCD=60°

In triangle DEF, angle DEF=180°-(40°+75°) = 65°

Hence angle A = 180°-(angle B + angle E)= 180°-(60°+65°) = 55°

Option D


Hope you mean to say that in triangle ACE,
Angle C + Angle E + Angle A = 180
60 + 65 + A = 180
A = 180 - 125 = 55

It seems to be a typo to write angle B..
Thanks!


Hi GMATAspirer09

thank you for highlighting it. will correct it.
GMAT Club Bot
Re: In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and li &nbs [#permalink] 18 Nov 2017, 06:51
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In the diagram, BC = CD = BD, angle FDE = 40°, angle EFD = 75°, and li

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