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18 Dec 2014, 15:27
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
71% (02:32) correct
29%
(03:01)
wrong
based on 190
sessions
History
Date
Time
Result
Not Attempted Yet
Attachment:
similar triangle diagram.JPG [ 15.8 KiB | Viewed 5832 times ]
(A) 175
(B) 350
(C) 775
(D) 1150
(E) 1575
For a set of practice problems on Similar Geometric Figures, as well as the OE for this particular problem, see:
https://magoosh.com/gmat/2014/gmat-pract ... c-figures/
Mike
18 Dec 2014, 15:33
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These are similar triangles, but small one is reversed. After noticing that, question is easily solved by proportion:
AE/BD=AC/CD=8/1
40*10*8/2 (area of big triangle) - 5*10/2 = 1575
Answer E
AE/BD=AC/CD=8/1
40*10*8/2 (area of big triangle) - 5*10/2 = 1575
Answer E
19 Dec 2014, 10:10
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Triangle BCD is similar to Triangle ACE having one right angle and one common angle.
Ratio of sides is 1:8, thus ratio of Area will be 1:64.
Area of BCD = (5*10)/2= 25
Area of ACE = 64*(Area of BCD) = 64*25 = 1600
Area of shaded region = Area of ACE - Area of BCD = 1600 - 25 = 1575
Answer E
Ratio of sides is 1:8, thus ratio of Area will be 1:64.
Area of BCD = (5*10)/2= 25
Area of ACE = 64*(Area of BCD) = 64*25 = 1600
Area of shaded region = Area of ACE - Area of BCD = 1600 - 25 = 1575
Answer E
