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In the equation x^2 – bx + 4 = 0, x is a variable and b is a constant.

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In the equation x^2 – bx + 4 = 0, x is a variable and b is a constant.  [#permalink]

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New post 20 Feb 2017, 04:58
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A
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D
E

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  25% (medium)

Question Stats:

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In the equation x^2 – bx + 4 = 0, x is a variable and b is a constant. What is the value of b?

(1) 2 is a root of the equation x^2 – bx + 4 = 0
(2) The average of the two real roots of the equation x^2 – bx + 4 = 0 is 2

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Re: In the equation x^2 – bx + 4 = 0, x is a variable and b is a constant.  [#permalink]

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New post 20 Feb 2017, 05:21
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duahsolo wrote:
In the equation x^2 – bx + 4 = 0, x is a variable and b is a constant. What is the value of b?

(1) 2 is a root of the equation x^2 – bx + 4 = 0
(2) The average of the two real roots of the equation x^2 – bx + 4 = 0 is 2


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Re: In the equation x^2 – bx + 4 = 0, x is a variable and b is a constant.  [#permalink]

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New post 20 Feb 2017, 05:23
1
duahsolo wrote:
In the equation x^2 – bx + 4 = 0, x is a variable and b is a constant. What is the value of b?

(1) 2 is a root of the equation x^2 – bx + 4 = 0
(2) The average of the two real roots of the equation x^2 – bx + 4 = 0 is 2


St I
2 is a root of the equation x^2 – bx + 4 = 0
Therefore 2^2 -2b+4=0 => 8 = 2b => b=4 -----------Sufficient

St II
The average of the two real roots of the equation x^2 – bx + 4 = 0 is 2
b is the sum of the roots of the equation, Therefore
b = average of the two real roots of the equation * 2 = 2 * 2 = 4 -----------Sufficient

Hence Option D is correct
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Re: In the equation x^2 – bx + 4 = 0, x is a variable and b is a constant.  [#permalink]

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New post 17 Jul 2018, 23:23
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Re: In the equation x^2 – bx + 4 = 0, x is a variable and b is a constant.   [#permalink] 17 Jul 2018, 23:23
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