Quote:
in statement 1 , please explain why we are considering c^2+4c > 0?
Thanks in adavance
andyjumpConsider below quadratic equation
\(ax^2 + bx + c = 0
\)
In what scenario the quadratic will have real solution .
The ans is, if the discriminant D of the equation is greater than zero .
\(ax^2 + bx + c = 0
\)
discriminant D >0 =>
\( b^2 - 4ac > 0\) where b , a , c are constants .
in statement 1 .. in this equation
\(x^2 − cx + c = 0
\)
c<0 (given)
So
D = \(b^2-4ac\) =>\( (-C)^2- 4(-C)\) > 0
=>\( C^2+4C\) > 0
Hope it helps..
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Thank you.
Regards,
AD“Start now. Optimize later.- An imperfect start can always be improved, but obsessing over a perfect plan will never take you anywhere on its own.”We are smart not because of our individual genius, but because of our collective knowledge.