Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
31 Oct 2018, 18:19
Kudos
Bookmarks
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
90% (00:37) correct
10%
(00:47)
wrong
based on 196
sessions
History
Date
Time
Result
Not Attempted Yet
In the figure above, the two square regions have areas 16 and 25, respectively. What is the area of the shaded triangular region?
A. 6
B. 8
C. 9
D. 12
E. 15
Attachment:
Geometry.PNG [ 2.72 KiB | Viewed 5975 times ]
31 Oct 2018, 19:41
Kudos
Bookmarks
Area of the first square = 16. Side = 4.
Area of the tilted square = 25. Side = 5.
The side of the tilted square becomes the hypotenuse of the triangle = 5.
The side of the first square becomes the height of the triangle. = 4.
Then by Pythagoras theorem, the base is 3.
Area of the triangle = 1/2*4*3 = 6.
A is the answer.
Area of the tilted square = 25. Side = 5.
The side of the tilted square becomes the hypotenuse of the triangle = 5.
The side of the first square becomes the height of the triangle. = 4.
Then by Pythagoras theorem, the base is 3.
Area of the triangle = 1/2*4*3 = 6.
A is the answer.
05 Nov 2019, 12:52
Kudos
Bookmarks
Hi All,
We're told that the two squares have areas 16 and 25, respectively. We're asked for the AREA of the shaded triangular region. This is an example of how the GMAT writers sometimes like to 'hide' the special Right Triangles (re: 3/4/5, 5/12/13, 30/60/90 and 45/45/90) in Geometry questions - and if you recognize the patterns involved, then you can answer this question relatively quickly without too much work.
To start, based on the areas of the two squares, we know that their respective sides are 4s and 5s. Thus, the right triangle has a height of 4 and a hypotenuse of 5. You probably recognize this as a 3/4/5 right triangle, but even if you didn't, you can use the Pythagorean Theorem to prove it:
A^2 + B^2 = C^2
A^2 + 4^2 = 5^2
A^2 + 16 = 25
A^2 = 9
A = 3... since this is a shape, it can't have a "negative" side (so -3 is not an option).
With a height of 4 and a base of 3, we can determine the AREA of the shape:
A = (1/2)(base)(height)
A = (1/2)(3)(4)
A = 6
Final Answer:
GMAT assassins aren't born, they're made,
Rich
We're told that the two squares have areas 16 and 25, respectively. We're asked for the AREA of the shaded triangular region. This is an example of how the GMAT writers sometimes like to 'hide' the special Right Triangles (re: 3/4/5, 5/12/13, 30/60/90 and 45/45/90) in Geometry questions - and if you recognize the patterns involved, then you can answer this question relatively quickly without too much work.
To start, based on the areas of the two squares, we know that their respective sides are 4s and 5s. Thus, the right triangle has a height of 4 and a hypotenuse of 5. You probably recognize this as a 3/4/5 right triangle, but even if you didn't, you can use the Pythagorean Theorem to prove it:
A^2 + B^2 = C^2
A^2 + 4^2 = 5^2
A^2 + 16 = 25
A^2 = 9
A = 3... since this is a shape, it can't have a "negative" side (so -3 is not an option).
With a height of 4 and a base of 3, we can determine the AREA of the shape:
A = (1/2)(base)(height)
A = (1/2)(3)(4)
A = 6
Final Answer:
GMAT assassins aren't born, they're made,
Rich
