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  • Typical Day of a UCLA MBA Student - Recording of Webinar with UCLA Adcom and Student

     December 14, 2018

     December 14, 2018

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    Carolyn and Brett - nicely explained what is the typical day of a UCLA student. I am posting below recording of the webinar for those who could't attend this session.
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In the figure above, the value of b is

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Posts: 51215
In the figure above, the value of b is  [#permalink]

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New post 03 Dec 2015, 05:33
1
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

87% (01:01) correct 13% (01:42) wrong based on 78 sessions

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In the figure above, the value of b is  [#permalink]

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New post Updated on: 03 Dec 2015, 05:54
4a=b+40 (vertically opposite) --1

5a+b+40=180 (sum =180) --2

from 1 b =4a-40

substituting it in eq 2

5a +4a-40+40=180
a=20

therefore b=40

Originally posted by CounterSniper on 03 Dec 2015, 05:39.
Last edited by CounterSniper on 03 Dec 2015, 05:54, edited 1 time in total.
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Re: In the figure above, the value of b is  [#permalink]

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New post 03 Dec 2015, 05:49
4a+5a = 180 (Angle on same line )
9a=180
a=20
Now b+40=4a=4*20=80(vertically opp angle)
b=40
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Re: In the figure above, the value of b is  [#permalink]

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New post 30 Apr 2016, 13:45
5a+4a = 180
a = 20
but vertically opposite angles on a pair of opposite lines are equal
4a = b +40
80 = a +40
a = 40
correct answer - B
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Re: In the figure above, the value of b is  [#permalink]

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New post 22 Feb 2018, 08:28
Bunuel wrote:
Image
In the figure above, the value of b is

A. 20
B. 40
C. 42
D. 80
E. 100

Attachment:
436.jpg


We can create the equation:

5a + 4a = 180

9a = 180

a = 20

and

b + 40 = 4a

b + 40 = 4(20)

b + 40 = 80

b = 40

Answer: B
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Re: In the figure above, the value of b is &nbs [#permalink] 22 Feb 2018, 08:28
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In the figure above, the value of b is

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