Finding the shaded area is equal to the area of the square less the area not shaded.
There are 4 "not shaded" regions.

Since we are given that AB = 4:
Area Square = \(4*4=16\).

We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):
Area Circle = \(\pi r^2 = pi (2)^2 = 4\pi\)

Therefore, the area of 2 "not-shaded" regions is:
\(16-4\pi\),

and the area of 4 "not-shaded" regions is:
\(2* (16-4\pi) = 32-8\pi\).

Since we know the area of the "pedals" is the area of the square less 4 "not shaded" regions:
\(16- (32-8\pi) = -16+8\pi = 8pi -16.\)

Therefore, the answer should be:
E. \(8\pi - 16\)

Area of the shaded region
= 8*[(area of quadrant)- (area of right angle triangle)]
= \(8*[{\frac{(pi*4)}{4}}- {\frac{1}{2}*2*2}]\)
= 8*(pi-2)

total area of the square = 16
and total area of the shaded region should be slightly less than 16
see answer options
A. \(8\pi\) 25 ; not possible
B. \(32 - 8\pi\) ; 7 ; too less
C. \(16 - 8\pi\) ; -ve value
D. \(8\pi - 32\) ; -ve value
E. \(8\pi - 16\) ; 9 slightly less than 16
IMO E;

Step Approach:

- Divide the Square in 4 equal sections(Squares) comprising of one shaded region(that will be a shaded region in square of side 2)
- area of triangle \(\frac{1}{2}∗2∗2=2\)
- area of circular region (it is exactly 1/4th of full circle) = \(\frac{1}{4}∗π∗r^2\) => radius is 2 => \(\frac{1}{4}∗π∗2^2 = π\)
- to get the area of shaded region we'll minus the area of triangle from entire circular region and multiple by 2 to cover full shaded region area. -> \(2(π−2)=(2π−4)\)
- we have 4 similar squares with shaded region, so we'll multiply the above result by 4 to get area covered by all 4 shaded regions: \(4*(2π−4) = 8π−16\)

IMO Option E

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Another way..

use of figure to simplify the question

Mark the areas as shown from a to h..
Now the area of semi-circle AB = a+b+c
the area of semi-circle BC = c+e+h
the area of semi-circle CD = f+g+h
the area of semi-circle DA = a+d+e
Area of all arcs =a+b+c+c+e+h+f+g+h+a+d+e= area of 4 semi-circles of radius 4/2 or 2 = \(2*\pi*r^2=2*\pi*2^2=8*\pi\)....(i)

Now area of square = a+b+c+d+e+f+g+h=4*4=16...(ii)

a+b+c+c+e+h+f+g+h+a+d+e-( a+b+c+d+e+f+g+h)=\(8\pi - 16\)......\(a+c+f+h=8\pi-16\)
And a+c+f+h is nothing but area of shaded region

E

Area of Square ABCD = 4 * 4 = 16
= Area of 4 petal regions + Area of non shaded regions
So,
Area of non shaded regions = 16 - Area of 4 petal regions

Area of semicircles with radius 2 = 4 * \(\pi\) \(2 * \frac{2}{2}\) = 8 * \(\pi\) (since there are 4 semicircles)
Here the area of semicircles include the shaded petals 's area twice as every petal is included in area of two semicircles.
Thus,
8 * \(\pi\) = Area of non - shaded regions + 2 * Area of Petal regions
= 16 - Area of 4 petal regions + 2 * Area of 4 petal regions (from equation in green)
= 16 + Area of 4 petal regions

Hence Area of 4 petal regions = 8 * \(\pi\) -16

IMO Answer E.
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it took me a lot of time until i got the idea to solve

if we can find the area of unshaded regions, we can subtract it from the area of square to get the answer.

if we look only two adjecent semi circles, and if we subtract the area of these adjecent semicircles, it will give us the area of two unshaded region. similarly, after again subtracting the area of two adjecent semicircles of another direction from the area of square, we will the area of remaining two unshaded portion.
Thus our quation for finding out the area of unshaded region is
(16 - 4pi)*2 = 32 - 8Pi

16 is the area of square and 4pi is the area of circle (two adjecent semicircle equal one circle).
ad we have multiplied this by two because, we have to find the areas of remaining two unshaded regions.
16 - 32 + 8pi
which is 8pi - 16