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In the formula a=b^2c, if b is multiplied by 2 and c is multiplied by

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In the formula a=b^2c, if b is multiplied by 2 and c is multiplied by [#permalink]

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Re: In the formula a=b^2c, if b is multiplied by 2 and c is multiplied by [#permalink]

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New post 12 Mar 2018, 22:02
Bunuel wrote:
In the formula \(a=b^2c\), if b is multiplied by 2 and c is multiplied by 3, then \(a\) must be multiplied by

A. 4
B. 6
C. 9
D. 12
E. 18


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Re: In the formula a=b^2c, if b is multiplied by 2 and c is multiplied by [#permalink]

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New post 13 Mar 2018, 05:02
Bunuel wrote:
In the formula \(a=b^2c\), if b is multiplied by 2 and c is multiplied by 3, then \(a\) must be multiplied by

A. 4
B. 6
C. 9
D. 12
E. 18


\(a=b^2c\)

if b is multiplied by 2 and c is multiplied by 3,


\(a_new=(2b)^2(3c)\)

\(a_new=12(b)^2(c)\)

i.e. a Must be multiples by 12

Answer: option D
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Re: In the formula a=b^2c, if b is multiplied by 2 and c is multiplied by [#permalink]

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New post 13 Mar 2018, 07:45
Bunuel wrote:
In the formula \(a=b^2c\), if b is multiplied by 2 and c is multiplied by 3, then \(a\) must be multiplied by

A. 4
B. 6
C. 9
D. 12
E. 18

Plug in b = 2 and c = 3

So, \(a = b^2c\) , ie \(a = 2^2*3\)

Hence, answer must be (D) 12
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In the formula a=b^2c, if b is multiplied by 2 and c is multiplied by [#permalink]

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New post 13 Mar 2018, 23:54
Bunuel wrote:
In the formula \(a=b^2c\), if b is multiplied by 2 and c is multiplied by 3, then \(a\) must be multiplied by

A. 4
B. 6
C. 9
D. 12
E. 18


a = b^2

Multiplying b by 2 we get 2b

Multiplying c by 3 we get 3c

Now, a = (2b)^2 * 3c

a = 12b^2 * c

a needs to be multiplied by 12 (D).
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Re: In the formula a=b^2c, if b is multiplied by 2 and c is multiplied by [#permalink]

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New post 14 Mar 2018, 16:01
Bunuel wrote:
In the formula \(a=b^2c\), if b is multiplied by 2 and c is multiplied by 3, then \(a\) must be multiplied by

A. 4
B. 6
C. 9
D. 12
E. 18


If b is multiplied by 2 and c is multiplied by 3, then we will have (2b)^2 * (3c) = 12b^2 * c, which is 12 times its original value. Since the right hand of the original equation has increased by a factor of 12, we must multiply the left side of the equation by 12 as well.

Answer: D
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In the formula a=b^2c, if b is multiplied by 2 and c is multiplied by [#permalink]

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New post 19 Mar 2018, 11:35

SOLUTION



We are given:
    • \(a\)= \(b^2\) c

If we multiply \(b\) by \(2\) and \(c\) by \(3\), then \(b\) becomes \(2b\) and \(c\) becomes \(3c\).
Thus, the new value of \(a\) is equal to:

    • =\((2b)^2\) *\((3c)\)
    • =\(4*\)\(b^2\)*\(3*c\)
    • = \(12\)* (\(b^2\) *\(c\))
    • =\(12*a\)
Therefore, \(a\) must be multiplied by \(12\).

Answer: D

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In the formula a=b^2c, if b is multiplied by 2 and c is multiplied by   [#permalink] 19 Mar 2018, 11:35
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