In the number line above, the ticks are evenly spaced. Which point rep

Question

A.png In the number line above, the ticks are evenly spaced. Which point represents 2^{10} ? A. A B. B C. C D. D E. E

niks18 · Accepted Answer

Distance between first two points  = 2^9-2^8=2^8(2-1)=2^8

As numbers are evenly spaced so it is an AP series with first term  a=2^8 , common difference  d=2^8  and  t_n=2^{10} . We need to find  "n"  i.e number of terms to reach to  2^{10}

t_n=a+(n-1)d => 2^{10}=2^8+(n-1)*2^8

or,  n = \frac{2^{10}}{2^8} = 4 . so fourth term will be  2^{10}  i.e point  B

Option  B

you can also arrive at point B once you know the distance between each point by simple counting.

generis · Answer

Find interval distance between known values

2^8 = 256  *  2  = 
 2^9 = 512

The distance between the points is  512 - 256 = 256

\frac{Difference}{IntervalLength}=  number of intervals

2^{10} = 1,024

1) To get there from  2^9 = 512 : 
 (1,024 - 512) = 512

512  is difference. Divide by length of interval.

\frac{512}{256} = 2  intervals

Between  2^9  and  2^{10}  there are two intervals of 256. Count up.

2) To get there from  2^8 = 256 : 
 (1,024 - 256) = 768

\frac{768}{256} = 3  intervals of 256. Count up.

2^{10}  is at point B.

Answer B

_|_256_|_256_|_256_|_256_|_256|_
_ 2^8 ____ 2^9 _____|_____ 2^{10} ____|_____|_
_ 2^8 ____ 2^9 _____A_____B______C_____D_

MathRevolution · Answer

=>

The distance between each pair of consecutive ticks is  2^9 – 2^8 = 2^8(2-1) = 2^8 . 
Find the values of each point: 
 A = 2^9 + 2^8. 
 B = A + 2^8 = 2^9 + 2^8 + 2^8 = 2^9 + 2*2^8 = 2^9 + 2^9 = 2*2^9 = 2^{10}.

Therefore, the answer is B.

Answer : B

ScottTargetTestPrep · Answer

We first must determine the distance between the evenly-spaced tick marks. We see that the distance between 2^8 and 2^9 is:

2^9 - 2^8 = 2^8(2^1 - 1) = 2^8

Let’s now determine how many tick marks we need, in order to get from 2^9 to 2^10. We can set up the following equation to determine k, the number of tick marks 2^10 is from 2^9:

2^9 + 2^8 x k = 2^10

Dividing both sides of the equation by 2^8, we have:

2 + k = 2^2

2 + k = 4

k = 2

Thus, 2 tick marks from 2^9 will be 2^10, which is point B.

Answer: B

akadiyan · Answer

2^8=256
2^9=512
2^10=1024

Points are evenly spaced. From first 2 points we can determine that spacing between 2 points is 256.

So from 2^9 to 2^10 is 512 which is 2 points from 2^9.

Answer is B

NDND · Answer

2^1  ___ 2^2  ___ 2^3  ___ 2^4  ___ 2^5

2 ____ 4 ____ 8____ 16 ___ 32

So the sequence is doubling, which means that on the number line above the distance between  2^9  and  2^{10}  will be double the distance between  2^8  and  2^9

B is the answer

bumpbot · Answer

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In the number line above, the ticks are evenly spaced. Which point rep

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In the number line above, the ticks are evenly spaced. Which point rep

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