Summer is Coming! Join the Game of Timers Competition to Win Epic Prizes. Registration is Open. Game starts Mon July 1st.

 It is currently 18 Jul 2019, 08:37

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# In the rectangular coordinate system above, for which of the

Author Message
TAGS:

### Hide Tags

Manager
Joined: 06 Feb 2010
Posts: 145
Schools: University of Dhaka - Class of 2010
GPA: 3.63
In the rectangular coordinate system above, for which of the  [#permalink]

### Show Tags

Updated on: 21 Jul 2014, 11:25
2
18
00:00

Difficulty:

5% (low)

Question Stats:

81% (01:17) correct 19% (01:13) wrong based on 500 sessions

### HideShow timer Statistics

Attachment:

Untitled.png [ 19.84 KiB | Viewed 17230 times ]
In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R only
E. P, Q, R and S

Attachment:

Clips.jpg [ 34.76 KiB | Viewed 21478 times ]

_________________
Practice Makes a Man Perfect. Practice. Practice. Practice......Perfectly

Critical Reasoning: http://gmatclub.com/forum/best-critical-reasoning-shortcuts-notes-tips-91280.html

Collections of MGMAT CAT: http://gmatclub.com/forum/collections-of-mgmat-cat-math-152750.html

MGMAT SC SUMMARY: http://gmatclub.com/forum/mgmat-sc-summary-of-fourth-edition-152753.html

Sentence Correction: http://gmatclub.com/forum/sentence-correction-strategies-and-notes-91218.html

Arithmatic & Algebra: http://gmatclub.com/forum/arithmatic-algebra-93678.html

I hope these will help to understand the basic concepts & strategies. Please Click ON KUDOS Button.

Originally posted by monirjewel on 22 Nov 2010, 06:29.
Last edited by Bunuel on 21 Jul 2014, 11:25, edited 1 time in total.
Edited the question
Math Expert
Joined: 02 Sep 2009
Posts: 56256
In the rectangular coordinate system above, for which of the  [#permalink]

### Show Tags

22 Nov 2010, 07:56
1
3

In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R only
E. P, Q, R and S

The area of a rectangle equals to $$area=width*length$$;

The area of a triangle equals to $$area=\frac{1}{2}*base*height$$ (also the area of a square=diagonal^2/2);

Now it's easy to calculate the areas of given figure:
$$area_P=\frac{1}{2}*4*1=2$$;
$$area_Q=1*2=2$$;
$$area_R=\frac{2^2}{2}=2$$;
$$area_S=\frac{1}{2}*3*1=1.5$$.

_________________
Manager
Joined: 13 Jul 2011
Posts: 83
Concentration: Operations, Strategy
GMAT 1: 680 Q46 V37
WE: Engineering (Telecommunications)
Re: In the rectangular coordinate system above, for which of the  [#permalink]

### Show Tags

20 Oct 2011, 22:26
1
1
1
Area of a triangle = 1/2 * Base * Height,
from the graph we can find out length of base and height of the triangles and rectangles.
P: Base = 4 Height = 1 Area = 1/2 (4)(1) = 2
Q: Base = 1 Height = 2 Area = Base * Height = 1 * 2 = 2
R: For a rhombus area can be calculated using the value of the diagonals ( D1 * D2 ) / 2
i:e (2*2)/2 = 2
S: Base = 3 Height = 1 Area = 1/2 (3)(1) = 1.5

Math Expert
Joined: 02 Sep 2009
Posts: 56256
Re: In the rectangular coordinate system above, for which of the  [#permalink]

### Show Tags

06 Mar 2014, 02:34
Bumping for review and further discussion.

_________________
Manager
Joined: 25 Sep 2012
Posts: 237
Location: India
Concentration: Strategy, Marketing
GMAT 1: 660 Q49 V31
GMAT 2: 680 Q48 V34
Re: In the rectangular coordinate system above, for which of the  [#permalink]

### Show Tags

04 May 2014, 03:05
Bunuel wrote:
In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R
E. P, Q, R and S

The area of a rectangle equals to $$area=width*length$$;

The area of a triangle equals to $$area=\frac{1}{2}*base*height$$ (also the area of a square=diagonal^2/2);

Now it's easy to calculate the areas of given figure:
$$area_P=\frac{1}{2}*4*1=2$$;
$$area_Q=1*2=2$$;
$$area_R=\frac{2^2}{2}=2$$;
$$area_S=\frac{1}{2}*3*1=1.5$$.

Hey Bunuel, How did you find the area of R? Did you divide it into two triangles?
And just for curiosity is that figure a square?

I got the right answer as I figured out the area of other three and the only option suitable was D
Math Expert
Joined: 02 Sep 2009
Posts: 56256
Re: In the rectangular coordinate system above, for which of the  [#permalink]

### Show Tags

04 May 2014, 03:14
2
2
b2bt wrote:
Bunuel wrote:
In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R
E. P, Q, R and S

The area of a rectangle equals to $$area=width*length$$;

The area of a triangle equals to $$area=\frac{1}{2}*base*height$$ (also the area of a square=diagonal^2/2);

Now it's easy to calculate the areas of given figure:
$$area_P=\frac{1}{2}*4*1=2$$;
$$area_Q=1*2=2$$;
$$area_R=\frac{2^2}{2}=2$$;
$$area_S=\frac{1}{2}*3*1=1.5$$.

Hey Bunuel, How did you find the area of R? Did you divide it into two triangles?
And just for curiosity is that figure a square?

I got the right answer as I figured out the area of other three and the only option suitable was D

Yes, it's a square because its diagonals are equal and perpendicular bisectors of each other. The area of a square=diagonal^2/2.

Does this make sense?

P.S. $$area_{square}=\frac{d^2}{2}$$ and $$area_{rhombus}=\frac{d_1*d_2}{2}$$.
_________________
Intern
Joined: 20 May 2014
Posts: 32
Re: In the rectangular coordinate system above, for which of the  [#permalink]

### Show Tags

21 Jul 2014, 10:54
Bunuel wrote:
b2bt wrote:
Bunuel wrote:
In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R
E. P, Q, R and S

The area of a rectangle equals to $$area=width*length$$;

The area of a triangle equals to $$area=\frac{1}{2}*base*height$$ (also the area of a square=diagonal^2/2);

Now it's easy to calculate the areas of given figure:
$$area_P=\frac{1}{2}*4*1=2$$;
$$area_Q=1*2=2$$;
$$area_R=\frac{2^2}{2}=2$$;
$$area_S=\frac{1}{2}*3*1=1.5$$.

Hey Bunuel, How did you find the area of R? Did you divide it into two triangles?
And just for curiosity is that figure a square?

I got the right answer as I figured out the area of other three and the only option suitable was D

Yes, it's a square because its diagonals are equal and perpendicular bisectors of each other. The area of a square=diagonal^2/2.

Does this make sense?

P.S. $$area_{square}=\frac{d^2}{2}$$ and $$area_{rhombus}=\frac{d_1*d_2}{2}$$.

Bunuel for calculating area of R : how did you get 2^2 /2 , where is 2 coming from? Can you explain the counting of boxes?

same question for S and Q
Math Expert
Joined: 02 Sep 2009
Posts: 56256
Re: In the rectangular coordinate system above, for which of the  [#permalink]

### Show Tags

21 Jul 2014, 11:30
sagnik2422 wrote:
Bunuel wrote:
Bunuel wrote:
In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R
E. P, Q, R and S

The area of a rectangle equals to $$area=width*length$$;

The area of a triangle equals to $$area=\frac{1}{2}*base*height$$ (also the area of a square=diagonal^2/2);

Now it's easy to calculate the areas of given figure:
$$area_P=\frac{1}{2}*4*1=2$$;
$$area_Q=1*2=2$$;
$$area_R=\frac{2^2}{2}=2$$;
$$area_S=\frac{1}{2}*3*1=1.5$$.

Yes, it's a square because its diagonals are equal and perpendicular bisectors of each other. The area of a square=diagonal^2/2.

Does this make sense?

P.S. $$area_{square}=\frac{d^2}{2}$$ and $$area_{rhombus}=\frac{d_1*d_2}{2}$$.

Bunuel for calculating area of R : how did you get 2^2 /2 , where is 2 coming from? Can you explain the counting of boxes?

same question for S and Q

R is a square --> the area of a square=diagonal^2/2 --> diagonal of R = 2 --> area = 2^2/2.

Q is a rectangle --> the area = length*width = 1*2.

S is a triangle --> the area = 1/2*base*height = 1/2*3*1 (consider vertical side as base).

Hope it's clear.
_________________
Intern
Joined: 20 May 2014
Posts: 32
Re: In the rectangular coordinate system above, for which of the  [#permalink]

### Show Tags

21 Jul 2014, 13:07
Great explanation, but how can I see that diagonal of R is 2? (like can you possibly label this on the diagram or give coordinates) also, I don't see how the width is 2 for the rectangle.

Sorry for the bother.
Intern
Joined: 20 May 2014
Posts: 32
Re: In the rectangular coordinate system above, for which of the  [#permalink]

### Show Tags

21 Jul 2014, 13:08
also how is the height 1 for S?
Math Expert
Joined: 02 Sep 2009
Posts: 56256
Re: In the rectangular coordinate system above, for which of the  [#permalink]

### Show Tags

21 Jul 2014, 13:12
sagnik2422 wrote:
Great explanation, but how can I see that diagonal of R is 2? (like can you possibly label this on the diagram or give coordinates) also, I don't see how the width is 2 for the rectangle.

Sorry for the bother.

Ask yourself how many units are there in the diagonal of R, in the width of the rectangle, ...

Sorry, I don't know how to explain it better.
_________________
Director
Joined: 06 Jan 2015
Posts: 681
Location: India
Concentration: Operations, Finance
GPA: 3.35
WE: Information Technology (Computer Software)
Re: In the rectangular coordinate system above, for which of the  [#permalink]

### Show Tags

24 Jan 2017, 07:35
monirjewel wrote:
Attachment:
Untitled.png
In the rectangular coordinate system above, for which of the shaded regions is the area 2?

A. None
B. Q Only
C. Q and R
D. P, Q and R only
E. P, Q, R and S

Attachment:
Clips.jpg

Hi,

By using logic, Calculate the area of P=(1/2)bh=>(1/2)(4)(1)=>2

Now see the options and quickly eliminate A,B,C (doesn't contain P)

Now calculate Are of S=(1/2)(3)(1) is not equal to 2 hence eliminate E

Ans:D
_________________
आत्मनॊ मोक्षार्थम् जगद्धिताय च

Resource: GMATPrep RCs With Solution
Manager
Joined: 16 May 2018
Posts: 83
Location: Hungary
Schools: Queen's MBA'20
Re: In the rectangular coordinate system above, for which of the  [#permalink]

### Show Tags

25 Jun 2019, 01:57
R is a square --> the area of a square=diagonal^2/2 --> diagonal of R = 2 --> area = 2^2/2.

About this, how did u figure that 2 is a diagonal and not a side length of square?
Re: In the rectangular coordinate system above, for which of the   [#permalink] 25 Jun 2019, 01:57
Display posts from previous: Sort by