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Joined: 21 Mar 2013
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In the rectangular coordinate system below, if OABC
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10 Jan 2014, 21:32
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In the rectangular coordinate system below, if OABC is a parallelogram and OA > OC, is the area of OABC > 50 ? Attachment:
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(1) The coordinates of point C are (5, 5). (2) The coordinates of point B are (0, 11).
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Re: In the rectangular coordinate system below, if OABC
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10 Jan 2014, 23:02
See attached figure. CD is perpendicular to OB. Area of parallelogram OABC = OB x CD. Statement 1: OD = 5. As, OA > OC, DB would have to be greater than 5. Hence OB > 5. Thus area of OABC > 50 (10 x 5) Sufficient Statement 2: We know OB = 11, but have no idea about CD. Hence, we have no measure of area of OABC. Insufficient Solution: A Regards Mnemonic Education Pvt Ltd ssingh@mnemoniceducation.com
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Re: In the rectangular coordinate system below, if OABC
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07 May 2014, 05:46
priyamne wrote: See attached figure. CD is perpendicular to OB. Area of parallelogram OABC = OB x CD. Statement 1: OD = 5. As, OA > OC, DB would have to be greater than 5. Hence OB > 5. Thus area of OABC > 50 (10 x 5) Sufficient Statement 2: We know OB = 11, but have no idea about CD. Hence, we have no measure of area of OABC. Insufficient Solution: A Regards Mnemonic Education Pvt Ltd ssingh@mnemoniceducation.comThanks Singh, could you please elaborate more on your explanation? First, why OD = 5? is the parallelogram symmetric across the yaxis? Also, I don't get how DB would have to be greater than 5. Statement 2 is more clear Thanks a lot buddy! Cheers! J



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Re: In the rectangular coordinate system below, if OABC
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07 May 2014, 07:43
jlgdr wrote: priyamne wrote: In the rectangular coordinate system below, if OABC is a parallelogram and OA > OC, is the area of OABC > 50 ? (1) The coordinates of point C are (5, 5). (2) The coordinates of point B are (0, 11). See attached figure. CD is perpendicular to OB. Area of parallelogram OABC = OB x CD. Statement 1: OD = 5. As, OA > OC, DB would have to be greater than 5. Hence OB > 5. Thus area of OABC > 50 (10 x 5) Sufficient Statement 2: We know OB = 11, but have no idea about CD. Hence, we have no measure of area of OABC. Insufficient Solution: A Regards Mnemonic Education Pvt Ltd ssingh@mnemoniceducation.comThanks Singh, could you please elaborate more on your explanation? First, why OD = 5? is the parallelogram symmetric across the yaxis? Also, I don't get how DB would have to be greater than 5. Statement 2 is more clear Thanks a lot buddy! Cheers! J Attachment:
Untitled.png [ 7.84 KiB  Viewed 3066 times ]
(1) The coordinates of point C are (5, 5). Why OD = 5? The ycoordinate of D is the same as that of C, so it's 5 > OD = 5. Is the parallelogram symmetric across the yaxis? It's not a mirror image around yaxis but the areas around it are the same. Also, I don't get how DB would have to be greater than 5. Since BC = OA and OA > OC, then BC > OC. Thus BD > (OD=5). Hope it's clear.
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Re: In the rectangular coordinate system below, if OABC
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20 Jun 2017, 07:11
Bunuel wrote: jlgdr wrote: priyamne wrote: In the rectangular coordinate system below, if OABC is a parallelogram and OA > OC, is the area of OABC > 50 ? (1) The coordinates of point C are (5, 5). (2) The coordinates of point B are (0, 11). See attached figure. CD is perpendicular to OB. Area of parallelogram OABC = OB x CD. Statement 1: OD = 5. As, OA > OC, DB would have to be greater than 5. Hence OB > 5. Thus area of OABC > 50 (10 x 5) Sufficient Statement 2: We know OB = 11, but have no idea about CD. Hence, we have no measure of area of OABC. Insufficient Solution: A Regards Mnemonic Education Pvt Ltd ssingh@mnemoniceducation.comThanks Singh, could you please elaborate more on your explanation? First, why OD = 5? is the parallelogram symmetric across the yaxis? Also, I don't get how DB would have to be greater than 5. Statement 2 is more clear Thanks a lot buddy! Cheers! J Attachment: Untitled.png (1) The coordinates of point C are (5, 5). Why OD = 5? The ycoordinate of D is the same as that of C, so it's 5 > OD = 5. Is the parallelogram symmetric across the yaxis? It's not a mirror image around yaxis but the areas around it are the same. Also, I don't get how DB would have to be greater than 5. Since BC = OA and OA > OC, then BC > OC. Thus BD > (OD=5). Hope it's clear. Little imagination helped me, but there is a calculation also to show how OB>10. As we know that the BC is greater than OC ( property of gram opposites sides equal), and by option A we fixed the point C (5,5) imagine a ladder BC reclining on wall ( yaxis in this case) and the only way the ladder can recline is if DB is greater than 5. Calculation  I dont know how to draw a figure on GMAT forum, so I will use the above given figure and try to explain as much as possible Lets call Angle DOC = x = 45 Degree ( as Point C is 5,5 ) and angle OBC = y. Now lets imagine BC is equal to OC. And hence <X=<Y = 45 Deg. Therefore Triangle OBC is a right angled triangle. Length of OC = BC = 5 sqt 2 ( \sqrt{5^2 + 5^2}) Therefore BO= \sqrt{OC^2 + BC^2}= 10 ( exactly) 1But since BC > CO , therefore angle y < angle x = 45 Deg . Therefor Angle BCO >90 Deg ( In a triangle Angle OBC= 180  x y)  2Equation 1 and 2 tells that BO>10. That ladder thing, I can explain if you require.



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Re: In the rectangular coordinate system below, if OABC
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19 Dec 2018, 07:00
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