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08 Jun 2020, 12:10
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B
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Difficulty:
25%
(medium)
Question Stats:
80% (01:34) correct
20%
(01:31)
wrong
based on 30
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In the rectangular solid above, if each dimension of the rectangular solid is an integer greater than 1 and the area of two sides of the solid is 14 and 18 respectively, what is the volume of the solid?
A. 42
B. 126
C. 252
D. 882
E. Cannot be Determined
Attachment:
1.png [ 3.16 KiB | Viewed 1324 times ]
08 Jun 2020, 12:25
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Let sides be a,b,c
Let ab=14
So Only Possible option either a=7or 2, b =2 or 7 respectively
Now bc =18 as b =2 , 7 not possible
c=9
Hence a=7,b=2,c=9
Volume =7*2*9=126
Let ab=14
So Only Possible option either a=7or 2, b =2 or 7 respectively
Now bc =18 as b =2 , 7 not possible
c=9
Hence a=7,b=2,c=9
Volume =7*2*9=126
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08 Jun 2020, 12:42
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The sides of cuboid is either LB , BH, HL (every two pair combination among them consist one side same, BH,HL or HB,BL, or HL, BL)
14 & 18 are two of the sides.
14 = 7*2
18 = 9*2
That mean sides of the cuboid = 9,7,2
The volume of box = 9*7*2 = 126
Answer is supposedly B
Posted from my mobile device
14 & 18 are two of the sides.
14 = 7*2
18 = 9*2
That mean sides of the cuboid = 9,7,2
The volume of box = 9*7*2 = 126
Answer is supposedly B
Posted from my mobile device
