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15 Nov 2019, 01:38
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
70% (02:17) correct
30%
(02:04)
wrong
based on 103
sessions
History
Date
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Not Attempted Yet
In the regular octagon above, what is x?
A. 157.5°
B. 150°
C. 145°
D. 135°
E. 120°
Are You Up For the Challenge: 700 Level Questions
Attachment:
Untitled.png [ 3.43 KiB | Viewed 3479 times ]
16 Nov 2019, 04:17
Kudos
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Bunuel
In the regular octagon above, what is x?
A. 157.5°
B. 150°
C. 145°
D. 135°
E. 120°
Are You Up For the Challenge: 700 Level Questions
Attachment:
The attachment Untitled.png is no longer available
Join B and C..
Take\( \triangle ADC......\angle{DAC}=135\) ( internal angle of octagon) and \(\angle{ADC}=\angle{ACD}=\frac{180-135}{2}=22.5\)( AD and AC are sides of Octagon)
Similarly take Take\( \triangle ADB......\angle{ADB}=135\) ( internal angle of octagon ) and \(\angle{DAB}=\angle{ABD}=\frac{180-120}{2}=22.5\)( sides of octagon )
Now take \(\triangle {ADO}\) and \(\triangle {BOC}\)..Both are similar as AD||BC.
Therefore \(\angle{DAB}=\angle{ABC}=22.5\) and \(\angle{ADC}=\angle{BCD}=22.5\)
Finally take \(\triangle{BOC}\)......Sum of angles = \(x+22.5+22.5=180....x=135\)
D
Attachments
Untitled (4).png [ 5.27 KiB | Viewed 3243 times ]
16 Nov 2019, 04:54
Kudos
Bookmarks
I think angle DAC is 135 because it octagon.
External angle is 45.
In the regular octagon above, what is x?
A. 157.5°
B. 150°
C. 145°
D. 135°
E. 120°
Are You Up For the Challenge: 700 Level Questions
Join B and C..
Take\( \triangle ADC......\angle{DAC}=120\) ( internal angle of hexagon) and \(\angle{ADC}=\angle{ACD}=\frac{180-120}{2}=30\)( AD and AC are sides of hexagon)
Similarly take Take\( \triangle ADB......\angle{ADB}=120\) ( internal angle of hexagon) and \(\angle{DAB}=\angle{ABD}=\frac{180-120}{2}=30\)( sides of hexagon)
Now take \(\triangle {ADO}\) and \(\triangle {BOC}\)..Both are similar as AD||BC.
Therefore \(\angle{DAB}=\angle{ABC}=30\) and \(\angle{ADC}=\angle{BCD}=30\)
Finally take \(\triangle{BOC}\)......Sum of angles = \(x+30+30=180....x=120\)
E
External angle is 45.
chetan2u
Bunuel
In the regular octagon above, what is x?
A. 157.5°
B. 150°
C. 145°
D. 135°
E. 120°
Are You Up For the Challenge: 700 Level Questions
Attachment:
Untitled.png
Join B and C..
Take\( \triangle ADC......\angle{DAC}=120\) ( internal angle of hexagon) and \(\angle{ADC}=\angle{ACD}=\frac{180-120}{2}=30\)( AD and AC are sides of hexagon)
Similarly take Take\( \triangle ADB......\angle{ADB}=120\) ( internal angle of hexagon) and \(\angle{DAB}=\angle{ABD}=\frac{180-120}{2}=30\)( sides of hexagon)
Now take \(\triangle {ADO}\) and \(\triangle {BOC}\)..Both are similar as AD||BC.
Therefore \(\angle{DAB}=\angle{ABC}=30\) and \(\angle{ADC}=\angle{BCD}=30\)
Finally take \(\triangle{BOC}\)......Sum of angles = \(x+30+30=180....x=120\)
E
