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03 Mar 2022, 07:30
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C
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89% (01:44) correct
11%
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In the right triangle below, side a is 7 inches longer than side b. If the area of the triangle is 30 inches^2, what is the length of hypotenuse c?
A. 11
B. 12
C. 13
D. 14
E. 15
Attachment:
2020-03-17_1650.png [ 9.69 KiB | Viewed 1667 times ]
03 Mar 2022, 07:42
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Bunuel
a = 7+b
Using Area Property, Area of ∆ \(= \frac{1}{2}*a*b = \frac{1}{2}*(7+b)*b = 30\)
i.e. (7+b)*b = 60
But 12*5 = 60
i.e. b = 5 and a = 7+5 = 12
ALso, Using pythagorus theorem, \(a^2+b^2 = c^2\)
i.e. \(12^2+5^2 = 13^2\)
i.e. c = 13
Answer: Option C
Archit3110
Major Poster
03 Mar 2022, 08:05
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another way
given that its a Pythagorus triplet possible set values ( 3 4 5;6 8 10;9 12 15; 5 12 13...)
difference b/w base and altitude is 7
so possible value of those two sides is 5,12
so hypotenuse would be 13
option C
given that its a Pythagorus triplet possible set values ( 3 4 5;6 8 10;9 12 15; 5 12 13...)
difference b/w base and altitude is 7
so possible value of those two sides is 5,12
so hypotenuse would be 13
option C
Bunuel
