monir6000
In the xy plane, line a and b have the same slope. If the y intercept of line a is -1. What is the y-intercept of line b?
(1) the x-intercept of line a is -1
(2) line b passess through the point (10, 20)
In the xy-plane, line a and line b have the same slope. If the y-intercept of line a is -1, what is the y-intercept of line b ? You don't need any algebra or even drawing, to solve this question. Just try to visualize the info given. First of all notice that "line a and line b have the same slope" means that the lines are parallel.
(1) The x-intercept of line a is -1. We have two points of line a: (0, -1) and (-1, 0), so it's fixed (we can find its equation). But since there are infinitely many parallel lines to line a, then each will have different y-intercept. Not sufficient.
(2 Line b passes through the point (10, 20). We have one point of line a: (0, -1) and one point of line b: (10, 20). We can rotate two parallel lines around these points, which will give different y-intercept of line b. Not sufficient.
(1)+(2) We have fixed line a, and its parallel line b which passes through the point (10, 20), which means that line b is also fixed and we can find its y-intercept (through some particular point, you can draw only one line which will be parallel to some fixed line). Sufficient.
Answer: C.
With the Statement 1, we have both the x and y intercepts of line a. So why do we have different pairs of lines . With the intercepts of both x and y , can't we determine the unique line or unique equation of line a ? Here x intercept is -1 and y-intercept is also -1. Please tell me where i am faltering.