Let equation of line l -->

\(y = Lx + a\)Let equation of line K -->

\(y = Kx + b\)Both line passes through (16/5, 12/5)

\(16L+5a = 12\) --Eq 1

\(16K+5b = 12\) --Eq2

(1) The product of the slopes of line l and line k is –1.

\(L * K=-1\) --Eq3

We have 3 equation and 4 unknown (a,b,L, M).

-- Not sufficient (2) Line k passes through the origin.

\(b = 0\)\(16K+5b = 12\) ==>

\(16K= 12\) ==>

\(\frac{3}{4}\) -- Not sufficient When we combine (1) and (2), L =

-\(\frac{4}{3}\) --Sufficient.

Ans C.
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