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08 Jun 2020, 11:57
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E
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In the xy-plane shown, is the slope of line l non-negative?
(1) The line passes through quadrants II and III.
(2) For each pair of coordinates (x,y) lying on line l, the product of x and y is not always non-negative.
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08 Jun 2020, 12:19
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IMO :- E
Option 1 :- Not sufficient
As, the line can pass to many points where, Slope can be greater than or less than zero
Option 2 :- Product of coordinate Pair x, y is sometimes Positive (info), it means it can be negative also
So it can pass from any co-ordinate
Hence Not Sufficient
Combining Both:-
Also not sufficient
Hence E
Option 1 :- Not sufficient
As, the line can pass to many points where, Slope can be greater than or less than zero
Option 2 :- Product of coordinate Pair x, y is sometimes Positive (info), it means it can be negative also
So it can pass from any co-ordinate
Hence Not Sufficient
Combining Both:-
Also not sufficient
Hence E
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08 Jun 2020, 13:27
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Statement 1: The line passes through quadrants II and III
(Now the slope can be upward slope, which is positive
Also, the slope can be downward making it negative)(Insufficient)
Statement 2: For each pair of coordinates (x,y) lying on line l, the product of x and y is not always non-negative.
Y=MX+C
Y*X = +ve value..
Both Y&X can be positive or negative
-Y = -MX+C {Negative Slope}
+Y = +MX+C {Positive Slope}
{Insufficient}
Statement 1&2: Coordinates of line From Statement 1&2 can't be put in a single equation (insufficient)
IMO E
Posted from my mobile device
(Now the slope can be upward slope, which is positive
Also, the slope can be downward making it negative)(Insufficient)
Statement 2: For each pair of coordinates (x,y) lying on line l, the product of x and y is not always non-negative.
Y=MX+C
Y*X = +ve value..
Both Y&X can be positive or negative
-Y = -MX+C {Negative Slope}
+Y = +MX+C {Positive Slope}
{Insufficient}
Statement 1&2: Coordinates of line From Statement 1&2 can't be put in a single equation (insufficient)
IMO E
Posted from my mobile device
