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In the xyplane, triangular region S is bounded by the lines x=0,y=0,
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30 Nov 2016, 03:05
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In the xyplane, triangular region S is bounded by the lines x=0,y=0, and 3x−2y=30. Which of the following points does NOT lie inside region S? A. (1,−1) B. (2,−10) C. (3,−13) D. (5,−5) E. (8,−2)
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In the xyplane, triangular region S is bounded by the lines x=0,y=0,
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30 Nov 2016, 04:01
This is how went with the problem, Drawn the shaded region with using three lines x=0, y=0 and 3x2y=30. Went back to the answer choices and putting the x values verified the y values. All the points falling in the region should follow equation 3x2y≤30. Only answer choice with point (3,−13) does now follow this equation and the value of the equation comes as 35 which is beyond the shaded region. Hope I am right ?
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Re: In the xyplane, triangular region S is bounded by the lines x=0,y=0,
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23 Feb 2017, 08:04
I just guessed the answer using the following method,
Using the equation 3x2y=30, we can find xintercept and yintercept if x=0, then y=15 if y=0, then x=10 after plotting it on the plane , find the midpoint of these 2 points (x1+x2/2, y1+y2/2)=(0+10/2,15+0/2)=>(5,7.5)
only one answer stands out (3,13) > D



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Re: In the xyplane, triangular region S is bounded by the lines x=0,y=0,
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24 Feb 2017, 06:24
Bunuel wrote: In the xyplane, triangular region S is bounded by the lines x=0,y=0, and 3x−2y=30. Which of the following points does NOT lie inside region S?
A. (1,−1) B. (2,−10) C. (3,−13) D. (5,−5) E. (8,−2) For the point to lie in the specified region 1) Point should be in 4th quadrant (all options are of 4th uadrant) 2) Since 3x−2y=30 i.e. y = (3/2)x15 so y must be greater than or equal to (3/2)x15 Checking options A. (1,−1) 1 > (3/2)(1)15 Hence, Point lies in the region hence Incorrect Option B. (2,−10) 10 > (3/2)(2)15 Hence, Point lies in the region hence Incorrect Option C. (3,−13) 13 < (3/2)(3)15 Hence, Point does NOT lie in the region hence CORRECT OptionD. (5,−5) 5 > (3/2)(5)15 Hence, Point lies in the region hence Incorrect Option E. (8,−2) 2 > (3/2)(8)15 Hence, Point lies in the region hence Incorrect Option Answer: Option C
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Re: In the xyplane, triangular region S is bounded by the lines x=0,y=0,
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15 Jun 2017, 22:47
GMATinsight wrote: Bunuel wrote: In the xyplane, triangular region S is bounded by the lines x=0,y=0, and 3x−2y=30. Which of the following points does NOT lie inside region S?
A. (1,−1) B. (2,−10) C. (3,−13) D. (5,−5) E. (8,−2) For the point to lie in the specified region 1) Point should be in 4th quadrant (all options are of 4th uadrant) 2) Since 3x−2y=30 i.e. y = (3/2)x15 so y must be greater than or equal to (3/2)x15 Checking options A. (1,−1) 1 > (3/2)(1)15 Hence, Point lies in the region hence Incorrect Option B. (2,−10) 10 > (3/2)(2)15 Hence, Point lies in the region hence Incorrect Option C. (3,−13) 13 < (3/2)(3)15 Hence, Point does NOT lie in the region hence CORRECT OptionD. (5,−5) 5 > (3/2)(5)15 Hence, Point lies in the region hence Incorrect Option E. (8,−2) 2 > (3/2)(8)15 Hence, Point lies in the region hence Incorrect Option Answer: Option C How do we know that the for the answer choices that y must be greater than the expression 3/2x  15? How do we know that it must be y is greater than that then say y must be less than that value?



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Re: In the xyplane, triangular region S is bounded by the lines x=0,y=0,
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15 Jun 2017, 23:01
Bunuel wrote: In the xyplane, triangular region S is bounded by the lines x=0,y=0, and 3x−2y=30. Which of the following points does NOT lie inside region S?
A. (1,−1) B. (2,−10) C. (3,−13) D. (5,−5) E. (8,−2) @Bunuel although we can diagram this problem, calculate the x and y intercepts which would inevitably allow us to find the answer can we not just reason that because we are given the hypotenuse of the triangle in this particular form 3x2y=30 that no set of coordinates within the triangle will result in a number greater than 30? And when I say hypotenuse of the triangle I want to note I am not trying to make a generalization there was another similar problem in ps made by manhattan in which the triangle in the plane had a x line and y line and an equation by the side it formed by connecting to the x and y lines turned out not to be the hypotenuse.



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Re: In the xyplane, triangular region S is bounded by the lines x=0,y=0,
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03 Apr 2018, 07:24
Hi, I do'nt understand why the point should satisfy the line eqn 3x2y < = 30 and not required to satify x <= 0 and y <= 0 as both are the eqn of lines that make the triangle. I don'nt know the concept or logic applied . kindly help me with the basic concepts here BunuelTIA



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Re: In the xyplane, triangular region S is bounded by the lines x=0,y=0,
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23 Apr 2019, 04:32
I have a different approach !
As per the graph mentioned by [#permalink] we are clear with x and y intercepts. the equation of the line becomes: y=(3/2)x 15
Slope of the line becomes 3/2 or 1.5 this means that when we move 1 unit in x we lose 1.5 units of y
Coming back to the question, All options have valid xaxis values. So, if we move 3 units in 3 we will lose 4.5 units of y intercept ie. y will be 154.5 = 10.5 But yaxis value is mentioned as 13, this shows that the point lies outside the region S.
Hope this helps !




Re: In the xyplane, triangular region S is bounded by the lines x=0,y=0,
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23 Apr 2019, 04:32






