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10 Sep 2019, 22:51
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In Tukitu village, one forth of the people are raising flowers, one ninth is growing wheat and one eleventh are going bankrupt. What could be the number of people in the village?
A. 792.
B. 540.
C. 346.
D. 198.
E. 132.
A. 792.
B. 540.
C. 346.
D. 198.
E. 132.
firas92
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10 Sep 2019, 23:04
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The total population must be divisible by 4, 9 and 11
346 and 198 are obviously not divisible by 4 since their last two digits do not make a multiple of 4
132 is not a multiple of 9 since sum of its digits is not a multiple of 9
540 is obviously not divisible by 11
This leaves us with 792, which is our answer
Answer is (A)
346 and 198 are obviously not divisible by 4 since their last two digits do not make a multiple of 4
132 is not a multiple of 9 since sum of its digits is not a multiple of 9
540 is obviously not divisible by 11
This leaves us with 792, which is our answer
Answer is (A)
11 Sep 2019, 09:33
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Bunuel
In Tukitu village, one forth of the people are raising flowers, one ninth is growing wheat and one eleventh are going bankrupt. What could be the number of people in the village?
A. 792.
B. 540.
C. 346.
D. 198.
E. 132.
A. 792.
B. 540.
C. 346.
D. 198.
E. 132.
common factor will be 4*9*11 ; 396 answer will be multiple of 396
in this case A ; 792
