Agree with D. But to simplyfy the solution, by reducing the number of variables,

Let V be abc. Then f(v) = \(2^a * 3^b * 5^c\).

Given, f(m) = 9f(v) ==> f(m) = \(2^a\) * \(3^(b+2)\) * \(5^c\)==> m = a(b+2)c.

Note: - Here m and v are expressed in terms face value.

m-v = a(b+2)c - abc. Consider the place value of each digit.

(100a + 10(b+2) + c) - (100a + 10b + c). Solving this we get 20.

So m-v = 20.

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