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Intern
Joined: 22 Apr 2019
Posts: 31

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08 Jun 2019, 07:06
Bunuel wrote:

Notice that $$(x+a)(x+b)(x+c)>0$$ can be written as $$(x-(-a))(x-(-b))(x-(-c))>0$$. So, if the "roots" of (x-a)(x-b)(x-c)>0 are a, b, and c, for $$(x-(-a))(x-(-b))(x-(-c))>0$$ they would be -a, -b, and -c.

For example, for (x + 1)(x + 2) > 0, you put on the line -1 and -2.

Hope it helps.

Ah perfect! Thanks!
Intern
Joined: 15 Jul 2019
Posts: 5

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23 Jul 2019, 18:18
Hi Karishma & Bunuel,

First of all, let me thank you to put together such an amazing explanation of Inequalities and strategies. It helped me immensely.

I have a small doubt in Step 2 mentioned in the very first post "Inequalities with Multiple Factors" of this thread:

"Starting from the rightmost section, mark the sections with alternate positive and negative signs. The inequality will be positive in the sections where you have the positive signs and it will be negative in the sections where you have the negative signs"

My understanding is that we have to check one value from each section to understand if the equation results in a Positive or Negative value in order to assign the sign to each of the section. is this correct? or we can blindly assign Positive and Negative sign to alternate sections respectively by starting with assigning Positive sign to the rightmost section?
Intern
Joined: 22 Apr 2019
Posts: 31

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23 Jul 2019, 18:22
shishirdixit wrote:
Hi Karishma & Bunuel,

First of all, let me thank you to put together such an amazing explanation of Inequalities and strategies. It helped me immensely.

I have a small doubt in Step 2 mentioned in the very first post "Inequalities with Multiple Factors" of this thread:

"Starting from the rightmost section, mark the sections with alternate positive and negative signs. The inequality will be positive in the sections where you have the positive signs and it will be negative in the sections where you have the negative signs"

My understanding is that we have to check one value from each section to understand if the equation results in a Positive or Negative value in order to assign the sign to each of the section. is this correct? or we can blindly assign Positive and Negative sign to alternate sections respectively by starting with assigning Positive sign to the rightmost section?

You can blindly assign assuming that it's set up correctly.
Intern
Joined: 19 Jun 2019
Posts: 2

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05 Aug 2019, 16:01
Hello Bunuel,

How did you factor this?

"Given: −2x3+17x2–30x>0−2x3+17x2–30x>0

x(−2x2+17x–30)>0x(−2x2+17x–30)>0 (taking x common)

Thanks

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