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Is 1/p>r/r^2+2? 1. p=r 2. r>0

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Is 1/p>r/r^2+2? 1. p=r 2. r>0 [#permalink]

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24 Aug 2008, 16:55
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Is 1/p>r/r^2+2?

1. p=r
2. r>0

Kudos [?]: 378 [0], given: 0

Manager
Joined: 12 Feb 2008
Posts: 177

Kudos [?]: 46 [0], given: 0

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24 Aug 2008, 17:36
vksunder wrote:
Is 1/p>r/r^2+2?

1. p=r
2. r>0

1. if p <0 is different answer than if p>0, thus insufficient
2. it doesnt tell us anything for p
combining them both tells us that p=r>0, sufficient

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SVP
Joined: 29 Aug 2007
Posts: 2472

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24 Aug 2008, 17:52
vksunder wrote:
Is 1/p>r/r^2+2?

1. p=r
2. r>0

1: if r = p >0, (1/p) > [(r)/(r^2+2)]. if not, then (1/p) < [(r)/(r^2+2)]. nsf..........
2: r = 0 doesnot tell much.....

togather r = p >0, (1/p) > [(r)/(r^2+2)].

suff...
C.
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24 Aug 2008, 18:10
A is tempting because it does prove that r/r^2-2 is closer to zero than 1/p, but you need the second part to be able to see which side of zero the inequality is on, so both are sufficient. This is an example of DS questions that give you enough with one to make assumptions about it but you must always remember there are two sides to a number line.

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Re: DSL Inequalities   [#permalink] 24 Aug 2008, 18:10
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