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Bunuel
Is 15 the average (arithmetic mean) of x, y, and 15?

(1) x + y= 30

(2) x - y = 4

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

The first step of the VA (Variable Approach) method is to modify the original condition and the question, and then recheck the question.

We can modify the question as follows.

The question asks if \((x+y+15)/3 = 15\).

\((x+y+15)/3 = 15\) ?
\(⇔ x + y + 15 = 45\) ?
\(⇔ x + y = 30\) ?

The equivalent question "\(x + y = 30\) ?" is same as the condition 1).

The condition 1) is sufficient.

Condition 2)
\(x = 17, y = 13\) : Yes
\(x = 5, y = 1\) : No
Since we don't have a unique answer, the condition 2) is not sufficient.

Therefore, A is the answer.
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