given Is \(2x < \frac{1}{x^2}\)?
simplify
2x-1/x^2<0
2x^3-1<0
2x^3<1
x^3<1/2
this is our target value now
#1
\(x^2 < 1\)
this relation would be valid for all values of -.9 to +.9
at x=0 we get yes to our target
at x= +0.8 we get no
insufficient
#2
\(|x| < \frac{1}{x}\)
this be valid for values of x from + .1 to .9
again we get yes and no for our target
yes till .1 to .5
and from .6 to .9
insufficient
from 1 &2
no 1 value of x satisfies given target
option E is correct
GMATinsight wrote:
Is \(2x < \frac{1}{x^2}\)?
1) \(x^2 < 1\)
2) \(|x| < \frac{1}{x}\)
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