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05 Nov 2019, 06:10
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
70% (01:47) correct
30%
(01:53)
wrong
based on 438
sessions
History
Date
Time
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Is \(7^x > 100\) ?
(1) \(7^{(x+2)} > 9,800\)
(2) \(7^{(2x)} > 10,000\)
Are You Up For the Challenge: 700 Level Questions
(1) \(7^{(x+2)} > 9,800\)
(2) \(7^{(2x)} > 10,000\)
Are You Up For the Challenge: 700 Level Questions
Updated on: 17 May 2021, 07:24
Originally posted by BrentGMATPrepNow on 05 Nov 2019, 06:55.
Last edited by BrentGMATPrepNow on 17 May 2021, 07:24, edited 1 time in total.
Last edited by BrentGMATPrepNow on 17 May 2021, 07:24, edited 1 time in total.
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Bunuel
Target question: Is \(7^x > 100\)
Statement 1: \(7^{(x+2)} > 9,800\)
Rewrite as: \((7^x)(7^2) > 9,800\)
In other words: \((7^x)(49) > 9,800\)
Divide both sides by 49 to get: \((7^x) > 200\)
Since 200 > 100, we can write: \((7^x) > 200 >100\)
So, the answer to the target question is YES, 7^x IS greater than 100
Since we can answer the target question with certainty, statement 1 is SUFFICIENT
Statement 2: \(7^{(2x)} > 10,000\)
Rewrite as: \((7^x)^2 > 100^2\)
This means: \(7^x > 100\)
The answer to the target question is YES, 7^x IS greater than 100
Since we can answer the target question with certainty, statement 2 is SUFFICIENT
Answer: D
Cheers,
Brent
RELATED VIDEO
General Discussion
05 Nov 2019, 10:21
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Is \(7^x > 100\) ?
Since \(7^3 = 343\), is x > 2 ?
(1) \(7^{x+2} > 9,800\)
\(7^x . 7^2 > 9800\)
\(7^x > 200\) (dividing both sides by 7^2)
x > 2
SUFFICIENT.
(2) \(7^{2x} > 10,000\)
Taking square root
\(7^x > 100\)
x >2
SUFFICIENT.
Answer D.
Since \(7^3 = 343\), is x > 2 ?
(1) \(7^{x+2} > 9,800\)
\(7^x . 7^2 > 9800\)
\(7^x > 200\) (dividing both sides by 7^2)
x > 2
SUFFICIENT.
(2) \(7^{2x} > 10,000\)
Taking square root
\(7^x > 100\)
x >2
SUFFICIENT.
Answer D.
