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elizabete634
Is a < b ?

(1) a^2 < ab
(2) b < 0

1. a^2<ab
ab is +ve since a^2 cant be -ve
a and b are both +ve or both -ve
a^2<ab means a*a<ab
a is common on both. Its the value of b that will impact the expression
If both +ve:
b>a
If both -ve:
b<a
No definite Y/N
Thus insufficient


2. No info about a

1+2:
b<0 thus both a and b are -ve
As discussed above for st.1, b<a
Thus definite answer
Hence sufficient

IMO C
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