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Bunuel
Is a ≠ b ?

(1) a^2 > b^2
(2) |a| < b

hey, please explain with an example.

For statement 1, if a = -2,b = 1, \(a^2 > b^2\) holds true
Now, substituting the values \(a^2 > b^2\) or 4 > 1.
However, if we try any value for a and b(which is equal), we will never get \(a^2 > b^2\).
We can clearly say that this statement will always result in a YES for a≠b
Hence sufficient.

Similarly for statement 2, if a = -3,b=4 |a| < b because 3 < 4. Clearly a≠b.
But, if we try any value for a and b, which is equal, we cannot have the condition |a| < b
We can clearly say that this statement will always result in a YES for a≠b
Hence sufficient.(Option D)

Hope it helps!
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Is a ≠ b ?

(1) a^2 > b^2
(2) |a| < b

Question Stem Analysis:

We need to determine whether a ≠ b. No other information is given in the question stem.

Statement One Alone:

\(\Rightarrow\) a^2 > b^2

If the squares of two numbers are not equal, then those two numbers cannot be equal either. Statement one alone is sufficient.

Eliminate answer choices B, C, and E.

Statement Two Alone:

\(\Rightarrow\) |a| < b

If |a| = a, then a < b, which means a ≠ b. If |a| = -a, then a < 0 and b > 0 (because b is greater than the absolute value of some number), which again means a ≠ b. In either case, a cannot be equal to b. Statement two alone is sufficient.

Answer: D
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