Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Notice that we are not told that a, b and c are integers.

Q: is \(a+b+c=even\)?

(1) \(a-c-b=even\), if the variables are integers then \(a+b+c\) will be even but if they are not, for example if \(a=3.5\), \(b=1\), \(c=0.5\) then \(a-c-b=2=even\), but \(a+b+c=5=odd\). Not sufficient.

(2) \(\frac{a-c}{b}=odd\). The same here: if the variables are integers then \(a+b+c\) will be even but if they are not for example if \(a=3.5\), \(b=1\), \(c=0.5\) then \(\frac{a-c}{b}=3=odd\), but \(a+b+c=5=odd\). Not sufficient

(1)+(2) \(a+b+c\) may or may not be even (again if variables are integers: YES but if \(a=3.5\), \(b=1\), \(c=0.5\) answer is NO). Not sufficient.

Re: Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is [#permalink]

Show Tags

08 Apr 2012, 09:53

Hi

+1 E

This is explained in the GMAT Club notes. I suggest you refer the Club Notes, cause when i first took a crack at this I choose A as well.
_________________

Giving +1 kudos is a better way of saying 'Thank You'.

Re: Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is [#permalink]

Show Tags

29 Jul 2012, 06:57

Bunuel wrote:

catty2004 wrote:

Is A + B + C even?

(1) A - C - B is even

(2) (A - C)/B is odd

Notice that we are not told that a, b and c are integers.

Q: is \(a+b+c=even\)?

(1) \(a-c-b=even\), if the variables are integers then \(a+b+c\) will be even but if they are not, for example if \(a=3.5\), \(b=1\), \(c=0.5\) then \(a-c-b=2=even\), but \(a+b+c=5=odd\). Not sufficient.

(2) \(\frac{a-c}{b}=odd\). The same here: if the variables are integers then \(a+b+c\) will be even but if they are not for example if \(a=3.5\), \(b=1\), \(c=0.5\) then \(\frac{a-c}{b}=3=odd\), but \(a+b+c=5=odd\). Not sufficient

(1)+(2) \(a+b+c\) may or may not be even (again if variables are integers: YES but if \(a=3.5\), \(b=1\), \(c=0.5\) answer is NO). Not sufficient.

Answer: E.

This question has more than I trap. Thanks for the explanation, Bunnel...!
_________________

The world ain't all sunshine and rainbows. It's a very mean and nasty place and I don't care how tough you are it will beat you to your knees and keep you there permanently if you let it. You, me, or nobody is gonna hit as hard as life. But it ain't about how hard ya hit. It's about how hard you can get it and keep moving forward. How much you can take and keep moving forward. That's how winning is done!

Re: Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is [#permalink]

Show Tags

29 Sep 2012, 22:44

Bunuel wrote:

catty2004 wrote:

Is A + B + C even?

(1) A - C - B is even

(2) (A - C)/B is odd

Notice that we are not told that a, b and c are integers.

Q: is \(a+b+c=even\)?

(1) \(a-c-b=even\), if the variables are integers then \(a+b+c\) will be even but if they are not, for example if \(a=3.5\), \(b=1\), \(c=0.5\) then \(a-c-b=2=even\), but \(a+b+c=5=odd\). Not sufficient.

(2) \(\frac{a-c}{b}=odd\). The same here: if the variables are integers then \(a+b+c\) will be even but if they are not for example if \(a=3.5\), \(b=1\), \(c=0.5\) then \(\frac{a-c}{b}=3=odd\), but \(a+b+c=5=odd\). Not sufficient

(1)+(2) \(a+b+c\) may or may not be even (again if variables are integers: YES but if \(a=3.5\), \(b=1\), \(c=0.5\) answer is NO). Not sufficient.

Answer: E.

Hi Bunuel,

Is this question, a good gmat candidate or not.
_________________

If you like my Question/Explanation or the contribution, Kindly appreciate by pressing KUDOS. Kudos always maximizes GMATCLUB worth-Game Theory

If you have any question regarding my post, kindly pm me or else I won't be able to reply

Notice that we are not told that a, b and c are integers.

Q: is \(a+b+c=even\)?

(1) \(a-c-b=even\), if the variables are integers then \(a+b+c\) will be even but if they are not, for example if \(a=3.5\), \(b=1\), \(c=0.5\) then \(a-c-b=2=even\), but \(a+b+c=5=odd\). Not sufficient.

(2) \(\frac{a-c}{b}=odd\). The same here: if the variables are integers then \(a+b+c\) will be even but if they are not for example if \(a=3.5\), \(b=1\), \(c=0.5\) then \(\frac{a-c}{b}=3=odd\), but \(a+b+c=5=odd\). Not sufficient

(1)+(2) \(a+b+c\) may or may not be even (again if variables are integers: YES but if \(a=3.5\), \(b=1\), \(c=0.5\) answer is NO). Not sufficient.

Answer: E.

Bunuel.. how can B will be even if it wud be mentioned that a b c are integers???
_________________

Bole So Nehal.. Sat Siri Akal.. Waheguru ji help me to get 700+ score !

Notice that we are not told that a, b and c are integers.

Q: is \(a+b+c=even\)?

(1) \(a-c-b=even\), if the variables are integers then \(a+b+c\) will be even but if they are not, for example if \(a=3.5\), \(b=1\), \(c=0.5\) then \(a-c-b=2=even\), but \(a+b+c=5=odd\). Not sufficient.

(2) \(\frac{a-c}{b}=odd\). The same here: if the variables are integers then \(a+b+c\) will be even but if they are not for example if \(a=3.5\), \(b=1\), \(c=0.5\) then \(\frac{a-c}{b}=3=odd\), but \(a+b+c=5=odd\). Not sufficient

(1)+(2) \(a+b+c\) may or may not be even (again if variables are integers: YES but if \(a=3.5\), \(b=1\), \(c=0.5\) answer is NO). Not sufficient.

Answer: E.

Bunuel.. how can B will be even if it wud be mentioned that a b c are integers???

Sorry, but I don't understand your question at all. Can you please elaborate what you mean? Thank you.
_________________

Re: Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is [#permalink]

Show Tags

01 Oct 2012, 09:29

Bunuel wrote:

catty2004 wrote:

Is A + B + C even?

(1) A - C - B is even

(2) (A - C)/B is odd

Notice that we are not told that a, b and c are integers.

Q: is \(a+b+c=even\)?

(1) \(a-c-b=even\), if the variables are integers then \(a+b+c\) will be even but if they are not, for example if \(a=3.5\), \(b=1\), \(c=0.5\) then \(a-c-b=2=even\), but \(a+b+c=5=odd\). Not sufficient.

(2) \(\frac{a-c}{b}=odd\). The same here: if the variables are integers then \(a+b+c\) will be even but if they are not for example if \(a=3.5\), \(b=1\), \(c=0.5\) then \(\frac{a-c}{b}=3=odd\), but \(a+b+c=5=odd\). Not sufficient

(1)+(2) \(a+b+c\) may or may not be even (again if variables are integers: YES but if \(a=3.5\), \(b=1\), \(c=0.5\) answer is NO). Not sufficient.

Answer: E.

I was asking abt statement 2.. U said..if it were mentioned that a b and c are intergers than A+b+c=even ..and then this statement wud b sufficient.. But i got this now..i have solved this ..bt i tuk some time while proving this statemt 2 ...
_________________

Bole So Nehal.. Sat Siri Akal.. Waheguru ji help me to get 700+ score !

Re: Is A + B + C even? (1) A - C - B is even (2) (A - C)/B is [#permalink]

Show Tags

11 Oct 2012, 10:54

1

This post received KUDOS

sanjoo wrote:

Bunuel wrote:

catty2004 wrote:

Is A + B + C even?

(1) A - C - B is even

(2) (A - C)/B is odd

Notice that we are not told that a, b and c are integers.

Q: is \(a+b+c=even\)?

(1) \(a-c-b=even\), if the variables are integers then \(a+b+c\) will be even but if they are not, for example if \(a=3.5\), \(b=1\), \(c=0.5\) then \(a-c-b=2=even\), but \(a+b+c=5=odd\). Not sufficient.

(2) \(\frac{a-c}{b}=odd\). The same here: if the variables are integers then \(a+b+c\) will be even but if they are not for example if \(a=3.5\), \(b=1\), \(c=0.5\) then \(\frac{a-c}{b}=3=odd\), but \(a+b+c=5=odd\). Not sufficient

(1)+(2) \(a+b+c\) may or may not be even (again if variables are integers: YES but if \(a=3.5\), \(b=1\), \(c=0.5\) answer is NO). Not sufficient.

Answer: E.

I was asking abt statement 2.. U said..if it were mentioned that a b and c are intergers than A+b+c=even ..and then this statement wud b sufficient.. But i got this now..i have solved this ..bt i tuk some time while proving this statemt 2 ...

It goes like this:

Q: Is A+B+C= EVEN

S1: A-B-C= Even i.e. We can write A-B-C= 2N =>A=2N + B+C Substituting in the main equation we get

2N+2(B+C)=2[N+B+C]

Now, N is an Integer, but we dont know whether, B+C= Integer or not. Hence N+B+C mayor may not be an Integer. Therefore, S1 is insufficient.

Same case with Statement 2, which on simplification gives, A=(2N+1)B + C => A+B+C= 2(B+C+NB)

Again same same scenario, We are not aware whether, the value in the parenthesis is an Integer or not.

Hence, S2 is also Insufficient.

S1 & S2 together also does not resolve the issue of whether B+C is integer or not.

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Note that we are not told that a, b and c are integers.

Q: is a+b+c=even?

(1) a-c-b=even, if the variables are integers then a+b+c will be even but if they are not: a=3.5, b=1, c=0.5 —> a-c-b=2=even, but a+b+c=5=odd. Not sufficient.

(2) \fraca-cb=odd. The same here: if the variables are integers then a+b+c will be even but if they are not: a=3.5, b=1, c=0.5 —> \fraca-cb=3=odd, but a+b+c=5=odd. Not sufficient

(1)+(2) a+b+c may or may not be even (again if variables are integers: YES but if a=3.5, b=1, c=0.5 answer is NO). Not sufficient.

Answer: E.

Course GMAT on-site in Chile Claudio Hurtado GMAT CHILE
_________________

claudio hurtado maturana Private lessons GMAT QUANT GRE QUANT SAT QUANT Classes group of 6 students GMAT QUANT GRE QUANT SAT QUANT Distance learning courses GMAT QUANT GRE QUANT SAT QUANT

Website http://www.gmatchile.cl Whatsapp +56999410328 Email clasesgmatchile@gmail.com Skype: clasesgmatchile@gmail.com Address Avenida Hernando de Aguirre 128 Of 904, Tobalaba Metro Station, Santiago Chile.

What a great question! I started this one writing out all the cases but then realized we don't know if a,b and c are integers. Got answer E and thought it took me at most 2.5 mins... nope just over 3:50. Although I finally got it, this question has made me realize I really need to improve my speed.
_________________

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

There’s something in Pacific North West that you cannot find anywhere else. The atmosphere and scenic nature are next to none, with mountains on one side and ocean on...

This month I got selected by Stanford GSB to be included in “Best & Brightest, Class of 2017” by Poets & Quants. Besides feeling honored for being part of...

Joe Navarro is an ex FBI agent who was a founding member of the FBI’s Behavioural Analysis Program. He was a body language expert who he used his ability to successfully...