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Bunuel
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(1) a^3(b − 2a) < 0
This means a^3 is negative or b-2a is negative. Does not tell us anything about a.
Insufficient

(2) 2a − b < 0
This means 2a < b. Again, no info on what is the sign of a
Insufficient

Combining both: We know 2a-b<0. So b-2a > 0. Applying this to the first equation, we now know a^3 is negative. This means a has to be negative.

Answer: C
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I'm probably missing something and may be wrong, but isn't the case that 3*(b-2a) would need to be odd rather than negative for the condition (<0) to be met? If (b-2a) is negative, while "a" remains positive the it will return a fraction?
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kaykaia
I'm probably missing something and may be wrong, but isn't the case that 3*(b-2a) would need to be odd rather than negative for the condition (<0) to be met? If (b-2a) is negative, while "a" remains positive the it will return a fraction?

The original question would benefit from some formatting.

You read statement (1) as \(a^{3(b − 2a)} < 0\), but Bunuel intended it to be \((a^3)(b − 2a) < 0\)
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