Hi fearinyoureye,
The question you're asking is reasonable based on how the information is 'presented' - but it's worth noting that we're dealing with a REMAINDER - and not simply an algebraic equation. Here's what that means:
In Fact 1, we're told that A divided by 3 equals C with a remainder of 2. This translates into:
A/3 = C remainder 2
The poster you're referring to wrote "C remainder 2" as "C + 2", which is fine, but you still have to remember that it's a REMAINDER.
If you want to isolate the A, then you multiply both sides by 3, BUT you do NOT multiply the remainder (since the remainder represents the "leftover pieces" and that part does NOT get tripled).
So
A = 3C + 2 (not A = 3C + 6)
Here is an example of that, using real numbers.....
Let's say A = 14
14/3 = 4 remainder 2
14 = 3(4) + 2
Notice how we ONLY multiply the '4' and NOT the '2' (since the remainder is not something that's being tripled - it's the 'leftover piece').
GMAT assassins aren't born, they're made,
Rich