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02 Dec 2017, 01:22
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
56% (01:29) correct
44%
(01:41)
wrong
based on 140
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Not Attempted Yet
\(d = \frac{x}{y}\)
In the expression above, x is an 8-digit integer and y is a 9-digit integer. Is d a decimal with exactly ten digits?
(1) The sum of all the digits in the numerator is not a multiple of 3.
(2) 33 is a factor of the denominator.
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Source: Self-Made
In the expression above, x is an 8-digit integer and y is a 9-digit integer. Is d a decimal with exactly ten digits?
(1) The sum of all the digits in the numerator is not a multiple of 3.
(2) 33 is a factor of the denominator.
------------------------
Source: Self-Made
02 Dec 2017, 07:14
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helloksin
Statement 1: implies \(x\) is not a multiple of \(3\). but nothing mentioned about \(y\). Insufficient
Statement 2: implies \(y\) is a multiple of \(3\). but nothing mentioned about \(x\). Insufficient
Combining 1 & 2, we know \(x\) is not a multiple of \(3\) & \(y\) is a multiple of \(3\), hence \(d\) will be a recurring decimal number.
so \(d\) will not have exactly ten digits after decimal point. Sufficient
Option C
ManishKM1
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02 Dec 2017, 08:03
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helloksin
1) Numerator is not a multiple of 3, but nothing is given for y. So insufficient.
2) Denominator is a multiple of 33, Hence a multiple of 3 and 11. No info for numerator. So insufficient.
Combining 1 & 2, the denominator is bound to have 3 since numerator is not a multiple of 3. So recurring decimal(1/3=.3333333333.., 2/3=0.6666666....) hence decimal with not exactly 10 digits. Hence C.
