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Re: Is d ≠ e ? (1) d > e + 1 (2) d < e + 2
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27 Feb 2017, 08:16
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Bunuel wrote:
Is d ≠ e ?
(1) d > e + 1 (2) d < e + 2
Target question:Is d ≠ e ? This is a good candidate for rephrasing the target question. If d = e, then we can say that d - e = 0 Likewise, if d ≠ e then we can say that d - e ≠ 0
REPHRASED target question:Is d - e ≠ 0 ?
Statement 1: d > e + 1 Subtract e from both sides to get: d - e > 1 If d - e is GREATER THAN 1, we can be certain that d - e will NEVER EQUAL ZERO. In other words, d - e ≠ 0 Since we can answer the REPHRASED target question with certainty, statement 1 is SUFFICIENT
Statement 2: d < e + 2 Subtract e from both sides to get: d - e < 2 If d - e is LESS THAN 2, it's POSSIBLE that d - e = 0, and it's POSSIBLE that d - e ≠ 0 Since we cannot answer the REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT
Answer: A
ASIDE: If you're not convinced that statement 2 is not sufficient, consider these two cases that yield contradictory answers to the target question: Case a: d = 3 and e = 2. In this case, d - e ≠ 0 Case b: d = 3 and e = 3. In this case, d - e = 0
Re: Is d ≠ e ? (1) d > e + 1 (2) d < e + 2
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27 Feb 2017, 07:35
1
Bunuel wrote:
Is d ≠ e ?
(1) d > e + 1 (2) d < e + 2
Question: Is d ≠ e ?
Statement 1: d > e + 1 i.e. d > 1 SUFFICIENT
Statement 2: d < e + 2 i.e. d and e may be equal and may be different too NOT SUFFICIENT
Answer: Option A
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56% (01:20) correct 
