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Is d ≠ e ? (1) d > e + 1 (2) d < e + 2

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Is d ≠ e ? (1) d > e + 1 (2) d < e + 2  [#permalink]

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New post 27 Feb 2017, 04:32
1
8
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A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

52% (01:20) correct 48% (01:23) wrong based on 160 sessions

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Re: Is d ≠ e ? (1) d > e + 1 (2) d < e + 2  [#permalink]

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New post 27 Feb 2017, 09:16
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Bunuel wrote:
Is d ≠ e ?

(1) d > e + 1
(2) d < e + 2


Target question: Is d ≠ e ?
This is a good candidate for rephrasing the target question.
If d = e, then we can say that d - e = 0
Likewise, if d ≠ e then we can say that d - e ≠ 0

REPHRASED target question: Is d - e ≠ 0 ?

Statement 1: d > e + 1
Subtract e from both sides to get: d - e > 1
If d - e is GREATER THAN 1, we can be certain that d - e will NEVER EQUAL ZERO.
In other words, d - e ≠ 0
Since we can answer the REPHRASED target question with certainty, statement 1 is SUFFICIENT

Statement 2: d < e + 2
Subtract e from both sides to get: d - e < 2
If d - e is LESS THAN 2, it's POSSIBLE that d - e = 0, and it's POSSIBLE that d - e ≠ 0
Since we cannot answer the REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT

Answer: A

ASIDE: If you're not convinced that statement 2 is not sufficient, consider these two cases that yield contradictory answers to the target question:
Case a: d = 3 and e = 2. In this case, d - e ≠ 0
Case b: d = 3 and e = 3. In this case, d - e = 0

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Re: Is d ≠ e ? (1) d > e + 1 (2) d < e + 2  [#permalink]

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New post 27 Feb 2017, 08:35
Bunuel wrote:
Is d ≠ e ?

(1) d > e + 1
(2) d < e + 2


Question: Is d ≠ e ?

Statement 1: d > e + 1
i.e. d > 1
SUFFICIENT

Statement 2: d < e + 2
i.e. d and e may be equal and may be different too
NOT SUFFICIENT

Answer: Option A
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Re: Is d ≠ e ? (1) d > e + 1 (2) d < e + 2  [#permalink]

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New post 28 Feb 2017, 05:01
GMATinsight wrote:

Question: Is d ≠ e ?

Statement 1: d > e + 1
i.e. d > 1
SUFFICIENT



Dear GMATInsight,

Why did you conclude that d>1.

If d=-2 & e=-4.............then....-2>-3
If d=-100 & e=-200 then ......-100>-199

So here d is not greater than 1.
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Re: Is d ≠ e ? (1) d > e + 1 (2) d < e + 2  [#permalink]

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New post 08 Oct 2018, 00:46
d>e+1
take any value d will never be equal to e
hence suff
statement 2
d<e+2
suppose e = 0
d<2
d can be 0
hence insuff
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Re: Is d ≠ e ? (1) d > e + 1 (2) d < e + 2   [#permalink] 08 Oct 2018, 00:46
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