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Bunuel
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Case 1:- let p= 5 and q= 1
Case 2:- Let p = 0.5 and q= -0.7

We cannot arrive to any answer

Ans E

Posted from my mobile device
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Bunuel
Is P > |Q|?

(1) P^2 > Q^3
(2) P > Q

Question: Is P > |Q|?

Statement 1:\( P^2 > Q^3\)

CAse 1: P = 2 and Q = 1, \(2^2 > 1^3\) and P > |Q|
CAse 2: P = 2 and Q = -3, \(2^2 > (-3)^3\) and P < |Q|

NOT SUFFICIENT

Statement 2: P > Q

CAse 1: P = 2 and Q = 1, \(2 > 1\) and P > |Q|
CAse 2: P = 2 and Q = -3, \(2 > (-3)\) and P < |Q|

NOT SUFFICIENT

COmbinig the statements

CAse 1: P = 2 and Q = 1, \(2^2 > 1^3\), P > Q and P > |Q|
CAse 2: P = 2 and Q = -3, \(2^2 > (-3)^3\), P > Q and P < |Q|

NOT SUFFICIENT

Answer: Option E
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Explanation:

Statement 1 : P^2 > Q^3
By taking different values for P & Q,
For, P=3;Q= 2, P^2 > Q^3 & P > |Q|
but When P=2, Q=-3, P^2 > Q^3 & P < |Q|
Not Sufficient.

Statement 2: P>Q
By taking different values for P & Q,
For, P=3;Q= 2, P>Q & P > |Q|
but When P=2, Q=-3, P>Q & P < |Q|
Not Sufficient.

From 1& 2
Not Sufficient

IMO-E
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Hello from the GMAT Club BumpBot!

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