|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
04 Dec 2019, 02:49
Kudos
Bookmarks
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
72% (01:30) correct
28%
(02:13)
wrong
based on 182
sessions
History
Date
Time
Result
Not Attempted Yet
Is the area of equilateral triangle E less than the area of square C ?
(1) A side of square C is \(\frac{2}{3}\) the length of a side of triangle E.
(2) The sum of the perimeters of triangle E and square C is 17
Are You Up For the Challenge: 700 Level Questions
(1) A side of square C is \(\frac{2}{3}\) the length of a side of triangle E.
(2) The sum of the perimeters of triangle E and square C is 17
Are You Up For the Challenge: 700 Level Questions
04 Dec 2019, 05:30
Kudos
Bookmarks
the question is: is\( \frac{\sqrt{3}}{4}t^2 < s^2\) ?
from statement (1), \(s = \frac{2}{3}t\)
so \(s^2 = \frac{4}{9}t^2\) > \(\frac{\sqrt{3}}{4}t^2\) --> sufficient
from statement (2), 3t+4s = 17 --> clearly insufficient because there is no restrictions for the values
A
from statement (1), \(s = \frac{2}{3}t\)
so \(s^2 = \frac{4}{9}t^2\) > \(\frac{\sqrt{3}}{4}t^2\) --> sufficient
from statement (2), 3t+4s = 17 --> clearly insufficient because there is no restrictions for the values
A
05 Jul 2021, 14:54
Kudos
Bookmarks
Automated notice from GMAT Club BumpBot:
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
