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Is the positive two-digit integer N less than 40 ?

(1) The units digit of N is 6 more than the tens digit --> the greatest possible value of the units digit is 9, thus the greatest possible value of the tens digit is 9-6=3, which means that N is less than 40. Sufficient.

(2) N is 4 less than 4 times the units digit. The same here: the greatest possible value of the units digit is 9, thus the greatest possible value of N is 4*9-4=32. Sufficient.

Re: Is the positive two-digit integer N less than 40 ? [#permalink]

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03 Dec 2012, 07:14

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I solved it using method of substitution.

Given number(N) is 2 digit number. So, 0<N<100. So, Question is whether N<40

Case 1: If Number N is AB, AB => A (A+6). AB => 17,28,39. hence, For sure, Number is less than 40. Option is sufficient to answer the question.

As Option A is sufficient to answer the question, Answer Choices C, E are eliminated.

Case 2: N is 4 less than 4 times the units digit. Let's N is AB N=> 4*B-4 => 4*(B-1) So, B should be greater than 5. If B =5, N =4 (Invalid case) If B =6, N =8 (Invalid case) IF B =7, N =24 If B =8, N =28 If B =9, N =32. So, For sure Number is less than 40. Option is sufficient to answer the question.

So, Either statement is sufficient to answer this question.

Re: Is the positive two-digit integer N less than 40 ? [#permalink]

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30 Dec 2012, 02:39

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When considering statement 2, isn't 28 the only correct number?

When units digit is 8, \((4*units)-4 = (4*8)-4 = 32 - 4 = 28\)

The units digit of N=28 is also 8. So technically, N=24 or N=32 do not even satisfy the condition. But for DS, I guess (4*9)-4 is the fastest and best way.
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When considering statement 2, isn't 28 the only correct number?

When units digit is 8, \((4*units)-4 = (4*8)-4 = 32 - 4 = 28\)

The units digit of N=28 is also 8. So technically, N=24 or N=32 do not even satisfy the condition. But for DS, I guess (4*9)-4 is the fastest and best way.

You are right: 28 is the only two-digit number which satisfies the second statement.
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Re: Is the positive two-digit integer N less than 40 ? [#permalink]

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12 Jan 2014, 08:30

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Re: Is the positive two-digit integer N less than 40 ? [#permalink]

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26 Jun 2014, 23:13

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Let no. be TU. (T- Ten's digit, U - Unit's digit). Also, since these are digits of a number & using the given constraint, 0<=U<=9, 1<=T<=9.

Required: 1<=T<=3 Constraints: 0<=U<=9, 1<=T<=9

A: U = T + 6 => T = U-6. Using constraints, U = 9,8,7; 1<=T<=9. This also results in 1<=T<=3. Hence, sufficient. B: 10T + U = 4U - 4 => T = (3U - 4)/10. Using constraints, U = 8; 1<=T<=9. This also results in 1<=T<=3. Hence, sufficient.

Re: Is the positive two-digit integer N less than 40 ? [#permalink]

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23 Oct 2014, 02:49

umeshpatil wrote:

I solved it using method of substitution.

Given number(N) is 2 digit number. So, 0<N<100. So, Question is whether N<40

Case 1: If Number N is AB, AB => A (A+6). AB => 17,28,39. hence, For sure, Number is less than 40. Option is sufficient to answer the question.

As Option A is sufficient to answer the question, Answer Choices C, E are eliminated.

Case 2: N is 4 less than 4 times the units digit. Let's N is AB N=> 4*B-4 => 4*(B-1) So, B should be greater than 5. If B =5, N =4 (Invalid case) If B =6, N =8 (Invalid case) IF B =7, N =24 If B =8, N =28 If B =9, N =32. So, For sure Number is less than 40. Option is sufficient to answer the question.

So, Either statement is sufficient to answer this question.

B=5 --> N=4*(B-1) = 4*(5-1)= 16 valid case similarly B=6 --> N=4*(B-1) = 4*(6-1)= 20 valid case

just wanted to correct you.

this in no way changes the answer but might confuse someone. So just trying to help.

Re: Is the positive two-digit integer N less than 40 ? [#permalink]

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10 Nov 2015, 03:14

Hello from the GMAT Club BumpBot!

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Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

Is the positive two-digit integer N less than 40 ?

(1) The units digit of N is 6 more than the tens digit. (2) N is 4 less than 4 times the units digit.

There are 3 variables (n,a,b) and 1 equation (n=10a+b) in the original condition, 2 equations in the given conditions, making it likely that (C) will be our answer. Looking at the conditions, For 1, n=17,28,39<40 answers the question yes, and is therefore sufficient. For 2, 10a+b=4b-4, 10a+4=3b, and this answers the question 'yes' for n=28<40. This is sufficient as well, making the answer seem like (D). However, this is a logic question with commonly made mistake type 4(B).

Hence, (C) also becomes the answer but if we apply integer commonly made mistake type 4, the answer still becomes (D).

For cases where we need 2 more equation, such as original conditions with “2 variables”, or “3 variables and 1 equation”, or “4 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 70% chance that C is the answer, while E has 25% chance. These two are the majority. In case of common mistake type 3,4, the answer may be from A, B or D but there is only 5% chance. Since C is most likely to be the answer using 1) and 2) separately according to DS definition (It saves us time). Obviously there may be cases where the answer is A, B, D or E.
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Re: Is the positive two-digit integer N less than 40 ? [#permalink]

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17 Nov 2016, 08:55

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