Answer is E.
We know that an integer divisible by 12 must be also divisible by all the 12 factors: 1,2,3,4,6 and 12. Hence: Must be EVEN, Their last 2 digits must be Divisible by 4 and the Sum of their digits must be a multiple of 3.
1) Lets Pick N=400, Divisible by 4 but it is not divisible by 3---->Not SUFF.
2) Lets Pick N=303, The hundreds digit and the units digit of n are divisible by 3 but is NOT EVEN.
Lets Pick N=336, The hundreds digit and the units digit of n are divisible by 3 and it is but it is EVEN.
We have 2 Different numbers--->Not SUFF.
Lets try C and use the info Together:
As we know the last digit must be multiple of 3 and Even so It is 6. The digit we are looking for _ _ 6. We also know the first digit must be 3,6 or 9 ----> 3_6; 6_6; 9_6. And we also know that the last two digits must be a multiple of 4. So terminating in 6 we only have 16,56 or 96.
The digit must be:
316 616 916
356 656 656
396 696 996
Lets Pick 316: 3+1+6=10 so it is not divisible by 3
Lets Pick 396: 3+9+6=18 divisible by 3
Two different numbers with two different outcomes---> Still Not SUFF--->ANSWER IS E