Last visit was: 18 Nov 2025, 23:41 It is currently 18 Nov 2025, 23:41
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
avatar
Ljchen121
Joined: 08 Mar 2012
Last visit: 27 Aug 2016
Posts: 4
Own Kudos:
67
 [43]
Schools: CBS '19 (S)
Schools: CBS '19 (S)
Posts: 4
Kudos: 67
 [43]
1
Kudos
Add Kudos
42
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 18 Nov 2025
Posts: 105,371
Own Kudos:
Given Kudos: 99,977
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,371
Kudos: 778,140
 [16]
16
Kudos
Add Kudos
Bookmarks
Bookmark this Post
General Discussion
avatar
Ljchen121
Joined: 08 Mar 2012
Last visit: 27 Aug 2016
Posts: 4
Own Kudos:
Schools: CBS '19 (S)
Schools: CBS '19 (S)
Posts: 4
Kudos: 67
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
sub3108
Joined: 01 Mar 2012
Last visit: 30 Mar 2015
Posts: 12
Own Kudos:
Given Kudos: 46
Concentration: Operations, Finance
GMAT 1: 740 Q49 V41
GPA: 3.3
WE:Engineering (Manufacturing)
GMAT 1: 740 Q49 V41
Posts: 12
Kudos: 6
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Initially tricked upon thinking it is E. Thanks Bunuel for the explanation.
User avatar
narangvaibhav
Joined: 30 Jun 2011
Last visit: 17 Aug 2012
Posts: 98
Own Kudos:
Given Kudos: 12
Affiliations: Project Management Professional (PMP)
Location: New Delhi, India
Concentration: Marketing
Posts: 98
Kudos: 160
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Ljchen121
I thought it was C, because the only way for the triangle to be isosceles given both conditions is for BC = AC , and that's not possible because side AC + BC (assuming they are the same length) would equal AB. And the third side of the triangle must be greater than the sum of the other two sides or less than the difference of the other two sides. So given both conditions, should we be able to say for sure that the triangle is not isosceles?

The OG says it's E though. Please help.

Answer should be E
even if we cosider both 1) & 2) consider the below examples:

Case 1--> x= 30, y=100 & third angle= 50
Case 2--> x=45, y=90 & third angle =45

here both 1) & 2) are satisfied but there is contradiction in result, i.e. in one case traingle is issoceles, in other it is not, for the same conditions. Hence E
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 18 Nov 2025
Posts: 105,371
Own Kudos:
778,140
 [2]
Given Kudos: 99,977
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,371
Kudos: 778,140
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
narangvaibhav
Ljchen121
I thought it was C, because the only way for the triangle to be isosceles given both conditions is for BC = AC , and that's not possible because side AC + BC (assuming they are the same length) would equal AB. And the third side of the triangle must be greater than the sum of the other two sides or less than the difference of the other two sides. So given both conditions, should we be able to say for sure that the triangle is not isosceles?

The OG says it's E though. Please help.

Answer should be E
even if we cosider both 1) & 2) consider the below examples:

Case 1--> x= 30, y=100 & third angle= 50
Case 2--> x=45, y=90 & third angle =45

here both 1) & 2) are satisfied but there is contradiction in result, i.e. in one case traingle is issoceles, in other it is not, for the same conditions. Hence E

When considering the statements together the red scenario is not possible. If x=z then it would mean that AC=BC. But in this case as given that AB=2BC then AB=BC+BC=BC+AC which is not possible because the length of any side of a triangle must be smaller than the sum of the other two sides.
User avatar
vibhav
Joined: 28 Dec 2010
Last visit: 13 Oct 2014
Posts: 212
Own Kudos:
Given Kudos: 33
Location: India
Posts: 212
Kudos: 810
Kudos
Add Kudos
Bookmarks
Bookmark this Post
intense reasoning guys! I picked E and didnt test the problem from the length of sides perspective. looked only at the angles.
User avatar
saggii27
Joined: 15 Jul 2012
Last visit: 31 Mar 2016
Posts: 24
Own Kudos:
Given Kudos: 245
Posts: 24
Kudos: 62
Kudos
Add Kudos
Bookmarks
Bookmark this Post
can side AB=AC from 1st statement by making x=y?
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 18 Nov 2025
Posts: 105,371
Own Kudos:
Given Kudos: 99,977
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,371
Kudos: 778,140
Kudos
Add Kudos
Bookmarks
Bookmark this Post
saggii27
can side AB=AC from 1st statement by making x=y?

Yes, for (1) it's possible that AB=AC as well as it's possible that AB#AC, so the first statement is not sufficient.
avatar
Shobhit7
Joined: 01 Feb 2017
Last visit: 29 Apr 2021
Posts: 240
Own Kudos:
Given Kudos: 148
Posts: 240
Kudos: 426
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi,

Basis Statement 1 alone: Given ratio of two sides of a triangle AB:BC as 2:1 and Triangle Inequality, how is it possible to create an isoslece triangle?

Please advice.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 18 Nov 2025
Posts: 105,371
Own Kudos:
778,140
 [1]
Given Kudos: 99,977
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,371
Kudos: 778,140
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Shobhit7
Hi,

Basis Statement 1 alone: Given ratio of two sides of a triangle AB:BC as 2:1 and Triangle Inequality, how is it possible to create an isoslece triangle?

Please advice.


2 - 2 - 1
Attachment:
MSP19491ghda5g6di30c1c600005766b2539c6cd6he.gif
MSP19491ghda5g6di30c1c600005766b2539c6cd6he.gif [ 2.99 KiB | Viewed 14765 times ]
User avatar
Nunuboy1994
Joined: 12 Nov 2016
Last visit: 24 Apr 2019
Posts: 558
Own Kudos:
Given Kudos: 167
Location: United States
Schools: Yale '18
GMAT 1: 650 Q43 V37
GRE 1: Q157 V158
GPA: 2.66
Schools: Yale '18
GMAT 1: 650 Q43 V37
GRE 1: Q157 V158
Posts: 558
Kudos: 124
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Ljchen121
Attachment:
Screen Shot 2012-05-08 at 1.05.37 PM.png
Note: Figure not drawn to scale.
Is triangle ABC an isosceles?

(1) AB/BC = 2

(2) x≠y

St 1

This statement just tells us that angle A = 2Y however we don't know for certain whether this is an isosceles because

2(50) + 50 + x =180
x =30

Or you could have an isosceles

2(45) + 45 +45 =180

But we can't make that decision unless we have more info

Insuff

St 2

Not necessarily

St 1 and St 2

If x cannot equal y then we cannot have an equilateral

C
User avatar
CEdward
Joined: 11 Aug 2020
Last visit: 14 Apr 2022
Posts: 1,203
Own Kudos:
Given Kudos: 332
Posts: 1,203
Kudos: 272
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Is this an OG question?

Can we reason this way?

Let's assume angle A is z.

St1. AB/BC = 2...this implies y = 2z...but insufficient b/c we don't know whether x = y
St2 x cannot equal y...insufficient b/c we don't know whether x = z

Combined:

3 angles - x, y, and z...each of which are distinct. Hence, ABC is NOT isosceles.

C.
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,583
Own Kudos:
Posts: 38,583
Kudos: 1,079
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Moderators:
Math Expert
105368 posts
496 posts