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Is x+1 a factor of 12?
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09 Sep 2010, 09:20
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67% (00:47) correct 33% (00:42) wrong based on 400 sessions
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Is x+1 a factor of 12? (1) x+1 is even (2) x+1 is a factor of 2 and 3
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Re: factors
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09 Sep 2010, 09:29




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Re: factors
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09 Sep 2010, 09:40
Thanks.. I had got confused between multiple and factor in statement 2... realized this basic goof after reading your post.



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Re: factors
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09 Sep 2010, 18:24
divisor, multiple and factor can be tricky when we are short of time...best is to write factors.. Question is Is x+1 = 1,2,3,4,6,12?
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Re: factors
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21 Dec 2012, 03:05
Bunuel wrote: agnok wrote: Is x+1 a factor of 12?
1. x+1 is even 2. x+1 is a factor of 2 and 3
Please explain your answer Good question. (1) x+1 is even > clearly insufficient, x+1 could be 2 or 30. (2) x+1 is a factor of 2 and 3 > 2 and 3 are consecutive integers, consecutive integers are coprime, which means that they do not share ANY common factor but 1 (for example 5 and 6, two consecutive integers share only one common factor: 1). So as x+1 is a factor of BOTH 2 and 3 then x+1=1 and 1 is a factor of 12. Sufficient. Answer: B. Bunuel, The reason I chose E was because of the case where x = 5 x + 1  even x + 1 = 6 is factor of both 2 & 3 But 12 is not a factor of 6
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Re: factors
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21 Dec 2012, 03:09
eaakbari wrote: Bunuel wrote: agnok wrote: Is x+1 a factor of 12?
1. x+1 is even 2. x+1 is a factor of 2 and 3
Please explain your answer Good question. (1) x+1 is even > clearly insufficient, x+1 could be 2 or 30. (2) x+1 is a factor of 2 and 3 > 2 and 3 are consecutive integers, consecutive integers are coprime, which means that they do not share ANY common factor but 1 (for example 5 and 6, two consecutive integers share only one common factor: 1). So as x+1 is a factor of BOTH 2 and 3 then x+1=1 and 1 is a factor of 12. Sufficient. Answer: B. Bunuel, The reason I chose E was because of the case where x = 5 x + 1  even x + 1 = 6 is factor of both 2 & 3But 12 is not a factor of 6 6 is NOT a factor (divisor) of neither 2 nor 3.
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Re: factors
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21 Dec 2012, 03:14
Yes, I mixed multiple and factors and made a massive mess. Thanks Bro. Much appreciated.
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Re: Is x+1 a factor of 12?
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21 Dec 2012, 05:13
Hi everyone! I might've missed something. But I got a question. Isn't statement (1) contradicting statement (2)? (1) > x+1 = even (2) > x+1 is a factor of 2 and 3. (Which gives us x+1 = 1) Wouldn't that mean that statement (1) is false? Again, I might've missed something.



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Re: Is x+1 a factor of 12?
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21 Dec 2012, 05:24
Hiho wrote: Hi everyone! I might've missed something. But I got a question. Isn't statement (1) contradicting statement (2)? (1) > x+1 = even (2) > x+1 is a factor of 2 and 3. (Which gives us x+1 = 1) Wouldn't that mean that statement (1) is false? Again, I might've missed something. Not at all 6,12,18,24,36... all are even numbers which have factors as 2 & 3
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Re: Is x+1 a factor of 12?
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21 Dec 2012, 05:50
eaakbari wrote: Hiho wrote: Hi everyone! I might've missed something. But I got a question. Isn't statement (1) contradicting statement (2)? (1) > x+1 = even (2) > x+1 is a factor of 2 and 3. (Which gives us x+1 = 1) Wouldn't that mean that statement (1) is false? Again, I might've missed something. Not at all 6,12,18,24,36... all are even numbers which have factors as 2 & 3 I'm not quite sure that I understand. x+1 is a factor of both 2 and 3. The only factor 2 and 3 shares is 1. Therefore x+1 = 1. Now what I don't understand is why statement (1) says that x+1 is even, when statement 2 gives us the solution that makes its odd.



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Re: Is x+1 a factor of 12?
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21 Dec 2012, 06:08
Hiho wrote: eaakbari wrote: Hiho wrote: Hi everyone! I might've missed something. But I got a question. Isn't statement (1) contradicting statement (2)? (1) > x+1 = even (2) > x+1 is a factor of 2 and 3. (Which gives us x+1 = 1) Wouldn't that mean that statement (1) is false? Again, I might've missed something. Not at all 6,12,18,24,36... all are even numbers which have factors as 2 & 3 I'm not quite sure that I understand. x+1 is a factor of both 2 and 3. The only factor 2 and 3 shares is 1. Therefore x+1 = 1. Now what I don't understand is why statement (1) says that x+1 is even, when statement 2 gives us the solution that makes its odd. Yes , you are correct. They are contradictory. Maybe statement B should read 'x+1 has factors 2 and 3' Its probably not a good source. Let Bunuel solve this confusion...XD
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Re: Is x+1 a factor of 12?
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21 Dec 2012, 06:27
eaakbari wrote: Hiho wrote: eaakbari wrote: Not at all
6,12,18,24,36...
all are even numbers which have factors as 2 & 3
I'm not quite sure that I understand. x+1 is a factor of both 2 and 3. The only factor 2 and 3 shares is 1. Therefore x+1 = 1. Now what I don't understand is why statement (1) says that x+1 is even, when statement 2 gives us the solution that makes its odd. Yes , you are correct. They are contradictory. Maybe statement B should read 'x+1 has factors 2 and 3' Its probably not a good source. Let Bunuel solve this confusion...XD I think it would be better if (1) would read ' x+1 = odd' instead. Your statement would make the question unsolvable because x+1 would have too many possible outcomes.



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Re: factors
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21 Dec 2012, 19:20
Bunnel according to statement1 X+1 is even but in our second statement we have derived X+1=1 which is an odd number .In real GMAT questions i do u think this kind of contradiction will be there in the two statements given ???



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Re: Is x+1 a factor of 12?
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21 Dec 2012, 20:12
Hiho wrote: Hi everyone! I might've missed something. But I got a question. Isn't statement (1) contradicting statement (2)? (1) > x+1 = even (2) > x+1 is a factor of 2 and 3. (Which gives us x+1 = 1) Wouldn't that mean that statement (1) is false? Again, I might've missed something. x+1 is a factor of both 2 and 3 that means the sum of x+1 can divide both 2 and 3 three. You see three no value common that divide both 2 and 3 other than 1 . 12 is also divisible by 1. Ans. B
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Re: factors
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Re: Is x+1 a factor of 12?
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04 Mar 2014, 05:30
Option B. S1: If x+1 is even x+1 could be 2 in which case answer is yes. x+1 could be 14 in which case answer is no. Not suff.
From S2:x+1 could only be 1,2 or 3 each of which is a factor of 12.So answer is yes.Suff.
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Re: Is x+1 a factor of 12?
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12 Mar 2014, 04:15
agnok wrote: Is x+1 a factor of 12?
(1) x+1 is even (2) x+1 is a factor of 2 and 3 Statement I is insufficient: x + 1 = 8, x + 1 = 4 Statement II is sufficient: If x + 1 is a factor of 2 and 3 it has to be equal to 1. Hence x + 1 is a factor of 12
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Re: Is x+1 a factor of 12?
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16 Mar 2016, 09:06
Excellent Question here statement 1 is not sufficient as x+1 can be 8 or 2 or 500 statement 2 tells us that x+1 is a factor of both 2 and 3 hence x+1=1 => x=0 thus as one is the FACTOR of every number => sufficient hence B
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Is x+1 a factor of 12?
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08 Dec 2018, 15:32
Is x+1 a factor of 12?
(1) x+1 is even (2) x+1 is a factor of 2 and 3
Silly mistakes all round, but gaps in my knowledge have been brought to light.
First I rewrote as is 12/(x+1) = int?
Stat.(1) I didn't put a constraint on the potential range of factors
Stat.(2) I actually interpreted as "x+1 is a factor of 2 and 3" therefore x is a factor of 6.
Applying the rules put forward by Bunuel:
(2) Two consecutive integers will never share the same prime factors, therefore the GCF of two consecutive integers is 1 Since x+1 is a factor of two consecutive integers (2 and 3), x+1 must be 1.
1 is a factor of 12. Thus Stat.(2) > Sufficient




Is x+1 a factor of 12? &nbs
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08 Dec 2018, 15:32






