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Is [m]x^2 > x[/m] ?

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Is [m]x^2 > x[/m] ?  [#permalink]

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New post 01 Dec 2018, 09:25
00:00
A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

55% (00:43) correct 45% (00:46) wrong based on 38 sessions

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GMATbuster's Weekly Quant Quiz#11 Ques #9


For Questions from earlier quizzes: Click Here


Is \(x^2 > x\) ?

(1) x is a prime number
(2) x ≥1

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Re: Is [m]x^2 > x[/m] ?  [#permalink]

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New post 01 Dec 2018, 09:50
[quote="workout"]

GMATbuster's Weekly Quant Quiz#11 Ques #9


For Questions from earlier quizzes: Click Here


Is \(x^2 > x\) ?

(1) x is a prime number
(2) x ≥1
i) x is prime ,so x can be 2,3 ,5,7...
Let x=2
So x^2 =4
4>2
So sufficient
ii) x>=1
So let x=1
So x^2=1
1 is not greater than 1
So not sufficient
Answer is A


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Re: Is [m]x^2 > x[/m] ?  [#permalink]

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New post 01 Dec 2018, 10:22
to find
x^2 > X
statement 1
x is a prime number
X^2> X is possible in every case

statement 1 is sufficient

statement 2
X > 1 or x=1
when x =1
then x^2 = x

when X > 1
x^2 > x

there are two cases

hence statement two not sufficient


answer is A option
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Re: Is [m]x^2 > x[/m] ?  [#permalink]

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New post 01 Dec 2018, 10:41
st 1. x is prime number sufficient because prime number cannot be negative and fraction x^2 is always greater than x
st2 x is equal or greater than 1 - sufficient
Answer is D

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Re: Is [m]x^2 > x[/m] ? &nbs [#permalink] 01 Dec 2018, 10:41
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