Arsh4MBA wrote:

pushpitkc wrote:

1. 2x + 1 is an integer

x can be 1 or \(\frac{1}{2}\). In both the cases, 2x + 1 is an integer,

but x=1 is an integer but x = \(\frac{1}{2}\) is not an integer. Insufficient

2. 5x – 1 is an integer

x can be 1 or \(\frac{1}{5}\). In both the cases, 5x - 1 is an integer,

but x=1 is an integer but x = \(\frac{1}{5}\) is not an integer. Insufficient

On combining the information from both the statements,

x has to be an integer (Sufficient) (Option C)

Hello

pushpitkc , I understand combining 1 & 2 helps to conclude if its an integer or not ?

But how are we sure its an integer. Can you throw some light?

Hi

Arsh4MBA,

On combining the information on both the statements,

the only option when both the expression 2x + 1 and 5x - 1 are integers is when x is an integer

If x is a fraction, the fraction has to have both 2 and 5 in its denominator.

The minimum such value of x is \(\frac{1}{(2*5)}\), but neither of the expressions will yield an integer

Hope that helps!

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