Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Aug 2710:00 AM EDT
-11:00 AM EDT
We’ve worked incredibly hard to build TTP into the best test prep experience possible, and it would mean a lot to us to win Newsweek’s 2026 Readers’ Choice Award for Best Test Prep. If TTP has helped you, we’d be incredibly grateful for your vote.
Sep 0410:00 AM PDT
-11:00 AM PDT
What does test anxiety really look like on the GMAT? For many test takers, it does not look like a panic attack. Instead, it shows up as brain fog, rereading, negative comparisons, mental noise....
Sep 0609:30 AM EDT
-12:30 PM EST
Top scores are possible when you enroll in a powerful EA course, taught live online + 6 months access to TTP OnDemand video courses included! Perfect class schedule and easy course access for working professionals. Class starts Sundays Sept. 6, 2026.- Sep 07
12:01 AM PDT
-11:59 PM PDT
On the 7th, GMAT Club Tests will be Free! Including all the Quizzes, Questions, and Tests. 12 AM - 11:59 PM PDT - Sep 09
07:00 AM PDT
-10:00 AM PDT
Meet AdComs and explore top Master’s programs - MiM, MiF, MSc, MSBA and more. - Application Fee Waivers - Free 1-Week of GMAT Club Tests: - Master's Application Toolkit - Grand Prize Giveaway 
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2108:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
24 Feb 2019, 00:15
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
65% (01:32) correct
35%
(01:39)
wrong
based on 231
sessions
History
Date
Time
Result
Not Attempted Yet
Is x > 3?
1) x >0
2) \(\sqrt{x^{3}-9x+4}\)>2
1) x >0
2) \(\sqrt{x^{3}-9x+4}\)>2
siddharthkapoor
GMAT Club Reviews PM Intern
Joined: 10 Apr 2018
Last visit: 12 Jul 2026
Posts: 527
Given Kudos: 522
Location: India
Schools: ISB'22 (D)
GMAT 1: 680 Q48 V34
GPA: 3.3
Products:
Updated on: 10 Oct 2019, 02:37
Originally posted by siddharthkapoor on 24 Feb 2019, 00:43.
Last edited by siddharthkapoor on 10 Oct 2019, 02:37, edited 6 times in total.
Last edited by siddharthkapoor on 10 Oct 2019, 02:37, edited 6 times in total.
Kudos
Bookmarks
Objective: To find if x>3
From statement 1) we know that x>0, but from this we can't say whether or not x>3. So option A and D can be eliminated.
From statement 2) we get:
x^3-9x+4>2^2
x^3-9x+4>4
=> x^3-9x>0
=> x(x+3)(x-3)>0, so from this we can't say whether x>3 or not as x>3 and -3<x<0 are both valid solutions, so option B and D can be eliminated.
Combining statement 1) and 2), we get:
x>0 and x>3 or -3<x<0
Thus, we can say that x>3, so option C is the correct option.
From statement 1) we know that x>0, but from this we can't say whether or not x>3. So option A and D can be eliminated.
From statement 2) we get:
x^3-9x+4>2^2
x^3-9x+4>4
=> x^3-9x>0
=> x(x+3)(x-3)>0, so from this we can't say whether x>3 or not as x>3 and -3<x<0 are both valid solutions, so option B and D can be eliminated.
Combining statement 1) and 2), we get:
x>0 and x>3 or -3<x<0
Thus, we can say that x>3, so option C is the correct option.
Updated on: 24 Feb 2019, 00:47
Originally posted by kumarankit01 on 24 Feb 2019, 00:46.
Last edited by kumarankit01 on 24 Feb 2019, 00:47, edited 1 time in total.
Last edited by kumarankit01 on 24 Feb 2019, 00:47, edited 1 time in total.
Kudos
Bookmarks
Answer is C .
1. x> 0 no sufficent
2. if we square both side ,
we get x^3-9x+4 > 4
=> x^3-9x>4
x(x^2 -9)>0
x(x-3)(x+3) >0
Not sufficent .
If we combine both,
we get x>0 , it means , x-3 should be greater than 0 or x >3
So answer is C . Both are sufficient.
Hit Kudos now ??
Posted from my mobile device
1. x> 0 no sufficent
2. if we square both side ,
we get x^3-9x+4 > 4
=> x^3-9x>4
x(x^2 -9)>0
x(x-3)(x+3) >0
Not sufficent .
If we combine both,
we get x>0 , it means , x-3 should be greater than 0 or x >3
So answer is C . Both are sufficient.
Hit Kudos now ??
Posted from my mobile device
