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Is x > y? (1) x + c > y + c (2) xc > yc

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Bunuel
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Is x > y? (1) x + c > y + c (2) xc > yc [#permalink] New post   07 Sep 2017, 23:41
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71% (00:48) correct 29% (01:14) wrong based on 56 sessions
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Is x > y?

(1) x + c > y + c
(2) xc > yc
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A
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Luckisnoexcuse
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Re: Is x > y? (1) x + c > y + c (2) xc > yc [#permalink] New post   07 Sep 2017, 23:45
Bunuel wrote:
Is x > y?

(1) x + c > y + c
(2) xc > yc



(1)subtracting c from both sides..sufficient
(2)we dont know the sign of c... not sufficient

A
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Mo2men
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Re: Is x > y? (1) x + c > y + c (2) xc > yc [#permalink] New post   09 Sep 2017, 03:05
Bunuel wrote:
Is x > y?

(1) x + c > y + c
(2) xc > yc


1) x + c > y + c

Cancel out c from both sides

x > y

Sufficient

(2) xc > yc

xc - yc > 0

c (x - y) > 0.............Two multiplied numbers to be positive is either both positive or both negative as follows:

x - y > 0... x > y & c > 0...Answer is yes

or

x - y < 0 ....x < y & c < 0...Answer is No

Insufficient

Answer: A
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Re: Is x > y? (1) x + c > y + c (2) xc > yc [#permalink] New post   09 May 2020, 20:21
Bunuel wrote:
Is x > y?

(1) x + c > y + c
(2) xc > yc


Is x > y?

(1) x + c > y + c
x > y
SUFFICIENT

(2) xc > yc
If c>0 ; x >y
But if c<0; y>x
NOT SUFFICIENT

IMO A
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Re: Is x > y? (1) x + c > y + c (2) xc > yc [#permalink]
09 May 2020, 20:21
Moderator:
Bunuel
Math Expert
92883 posts

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