Bunuel wrote:

Is x > y ?

(1) x + y > 0

(2) x^2 – y^2 > 0

Check Points : Positive , negative and neutral test cases.

Assumption : Lets assume condition 1 to be true . We have x+y > 0

Negative test case : x=-5, y=7. x+y>0 Yes

Is X > y . Answer No

Positive test case : x=7, y=5. x+y>0 Yes

Is x>y . Answer Yes

We do not have a definite answer to this answer choice. Hence A is not sufficient.

Assumption : Lets assume condition 2 to be true . We have x^2 – y^2 > 0. Breaking it down leads to (x+y)(x-y) > 0

=>if ( x+y ) is positive, (x-y) has to be positive

=> if (x+y) is negative, (x-y) has to be negative to make the assumption true.

Checkpoints : All positive , negative and neutral values of x and y

Let x=-5, y=7. x+y is positive, x-y is negative. Does not meet the condition

Let x=5, y=7. x+y is positive and x-y is negative. Does not meet the condition.

Let x=7, y=-5. x+y is positive, x-y is positive. Satisfys the condition.

Let x=7, y=5. x+y is positive, x-y is positive. Satisfys the condition.

Inference, x has to be greater than y to satisfy option B.

Hence, option B is sufficient to answer the question.

Choice B is correct.

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