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# Is x > y? (1) x - y - 1 > 0 (2) x - y + 1 > 0

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Re: Is x > y? (1) x - y - 1 > 0 (2) x - y + 1 > 0 [#permalink]
The question can be rephrased as "Is x-y > 0? "

(1) x - y - 1 > 0
or x - y > 1 , hence > 0
Suff

(2) x - y + 1 >
or x - y > -1 , may or may not be > 0
NOT Suff

Bunuel
Is x > y?

(1) x - y - 1 > 0

(2) x - y + 1 > 0

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Re: Is x > y? (1) x - y - 1 > 0 (2) x - y + 1 > 0 [#permalink]
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