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01 May 2020, 03:17
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
41% (02:27) correct
59%
(02:22)
wrong
based on 98
sessions
History
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Time
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Not Attempted Yet
Is \(x > y\) ?
(1) \(x \geq (y - 2)^2 - 1\)
(2) \(y < |x|\)
Are You Up For the Challenge: 700 Level Questions
(1) \(x \geq (y - 2)^2 - 1\)
(2) \(y < |x|\)
Are You Up For the Challenge: 700 Level Questions
ArunSharma12
Joined: 25 Oct 2015
Last visit: 20 Jul 2022
Posts: 513
Given Kudos: 74
Location: India
Schools: IIML-IPMX '22 (A)
GMAT 1: 650 Q48 V31
GMAT 2: 720 Q49 V38 (Online)
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Updated on: 02 May 2020, 01:48
Originally posted by ArunSharma12 on 01 May 2020, 05:47.
Last edited by ArunSharma12 on 02 May 2020, 01:48, edited 1 time in total.
Last edited by ArunSharma12 on 02 May 2020, 01:48, edited 1 time in total.
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Bunuel
statement 1:
\(x \geq (y - 2)^2 - 1\)
\(x +1 \geq 0\), \((y-2)^2\) will always be 0 or positive
\(x \geq -1\)
value of y is not known
not sufficient
statement 2:
\(y < |x|\)
x can be positive or negative
not sufficient
combining both statements,
x can be 5 & y can be less than 5. ; x > y
not sufficient
Ans: E
when x < 0
\(0 \geq (y - 2)^2 - 1\)
\(1 \geq (y - 2)^2 \)
\(-1 \leq (y - 2) \leq 1 \)
\(1 \leq y \leq 3 \) & statement 2 says |x|>y
there is no value of y within this range that can be less than \(-1 \leq x \leq 0\). hence x > 0
thus x > y
ans: C
01 May 2020, 19:39
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Bunuel
(1) \(x \geq (y - 2)^2 - 1\)
Straight way we can say that when \(y=2\), \(x\geq{-1}\), so x can be -1, 0, 2, 10...
As the least value of \((y-2)^2\) is 0, we can say that \(x\geq{-1}\)
Insuff
(2) \(y < |x|\)
If x is positive..Yes.......y<|x|=x
If x is negative..Can be yes or NO.....y=-3, x=-2 OR y=-3 and x=-5
Insuff
Combined...
From \(x \geq (y - 2)^2 - 1\), we will have x as NEGATIVE or 0 only when \( (y - 2)^2\leq 1\) or \(1\leq y \leq 3\), but \(x\geq{-1}\). This means it will never be possible that y<|x| when x is negative or 0.
Thus x>0, and as per \(y<|x|=x\), we get YES as the answer.
C
