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mojorising800
Joined: 11 Dec 2009
Last visit: 05 Mar 2012
Posts: 111
Given Kudos: 7
Status:Its Wow or Never
Location: India
Concentration: Technology, Strategy
Schools: Tepper '14 Goizueta '14 ISB Tippie Kelley '14 Georgia Tech Mays Katz Kenan-Flagler '14 Schulich Smith '15
GMAT 1: 670 Q47 V35
GMAT 2: 710 Q48 V40
WE:Information Technology (Computer Software)
Schools: Tepper '14 Goizueta '14 ISB Tippie Kelley '14 Georgia Tech Mays Katz Kenan-Flagler '14 Schulich Smith '15
GMAT 2: 710 Q48 V40
Posts: 111
05 Jul 2011, 02:46
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
71% (01:05) correct
29%
(01:08)
wrong
based on 155
sessions
History
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05 Jul 2011, 03:18
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mojorising800
can somebody please explain this.Looks a very easy question but i am confused about the OE given.
Is x > y?
(1) x^2 > y
(2) x – |y| > 0
Is x > y?
(1) x^2 > y
(2) x – |y| > 0
Statement 1 is clearly not sufficient alone. Only if we know that x > x^2, will we get a definite answer. But x > x^2 only when x lies between 0 and 1 which is not given. So statement 1 is not sufficient.
Statement 2 tells you that x > |y|. This means x is greater than the absolute value of y. Then x has to be greater than y too.
Think about it: |y| is either equal to y (when y is +ve or 0) or it is greater than y (when y is negative). So if x is greater than |y|, it has to be greater than y too.
You can also take an example to understand this.
Say y = -4
Given x > |y| i.e. x > 4
Then x has to be greater than -4 too.
Say y = 4
Given x > |y| i.e. x > 4
In either case, x has to be greater than y.
So statement 2 alone is sufficient.
05 Jul 2011, 03:49
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mojorising800
can somebody please explain this.Looks a very easy question but i am confused about the OE given.
Is x > y?
(1) x^2 > y
(2) x – |y| > 0
Is x > y?
(1) x^2 > y
(2) x – |y| > 0
The best way is to test cases.
1) take x=-2, y=1 and x=2 , y=1. NS
2) rewrite it , so x>|y|
in this case x is positive , so x>0 , thus in any case of y whether positive or negative x>y.
